关于static const小弟我真的是不知道错哪了

关于static const我真的是不知道哪里错了~
#include <string>
#include <iostream>
using   namespace   std;

class   StringStack
{
static   const   int   size=100;
const   string*   stack[size];
int   index;
public:
StringStack();
void   push(const   string*   s);
const   string*   pop();
};

StringStack::StringStack():index(0){
memset(stack,0,size*sizeof(string*));
}

void   StringStack::push(const   string*   s)
{
if(index <size)
stack[index++]=s;
}

const   string*   StringStack::pop(){
if(index <0){
const   string*   rv=stack[--index];
stack[index]=0;
return   rv;
}
return   0;
}

string   iceCream[]={
"hello ",
"shit ",
"ok "
};

const   int   iCsz=sizeof   iceCream/sizeof*iceCream;

int   main()
{
StringStack   ss;
for(int   i=0;i <iCsz;i++)
ss.push(&iceCream[i]);
const   string*   cp;
while((cp=ss.pop())!=0)
cout < <*cp < <endl;
}
E:\CAndCpp\book\StringStack.cpp(7)   :   error   C2258:   illegal   pure   syntax,   must   be   '=   0 '
E:\CAndCpp\book\StringStack.cpp(7)   :   error   C2252:   'size '   :   pure   specifier   can   only   be   specified   for   functions
E:\CAndCpp\book\StringStack.cpp(8)   :   error   C2065:   'size '   :   undeclared   identifier
E:\CAndCpp\book\StringStack.cpp(8)   :   error   C2057:   expected   constant   expression
E:\CAndCpp\book\StringStack.cpp(8)   :   warning   C4200:   nonstandard   extension   used   :   zero-sized   array   in   struct/union
E:\CAndCpp\book\StringStack.cpp(9)   :   error   C2229:   class   'StringStack '   has   an   illegal   zero-sized   array
E:\CAndCpp\book\StringStack.cpp(51)   :   warning   C4508:   'main '   :   function   should   return   a   value;   'void '   return   type   assumed
Error   executing   cl.exe.

StringStack.exe   -   5   error(s),   2   warning(s)

哪位大哥帮我纠错啊，谢谢了！

[解决办法]
vc6吧。要么换编译器，要么用enum代替static const
[解决办法]
static const int size=100;
==========================
这个只声明初始值，未分配的内存
需在类外定义const int StringStack：：size；以分配内存的
[解决办法]
vs2005下是这个错误 cout < <*cp < <endl;

error C2679: binary ' < < ' : no operator found which takes a right-hand operand of type 'const std::string ' (or there is no acceptable conversion)
[解决办法]
#include <string>
#include <iostream>
using namespace std;

static const int size=100;
class StringStack
{
const string* stack[size];
int index;
public:
StringStack();
void push(const string* s);
const string* pop();
};

StringStack::StringStack():index(0){

memset(stack,0,size*sizeof(string*));
}

void StringStack::push(const string* s)
{
if(index <size)
stack[index++]=s;
}

const string* StringStack::pop(){
if(index> 0){
const string* rv=stack[--index];
stack[index]=0;
return rv;
}
return 0;
}

string iceCream[]={
"hello ",
"shit ",
"ok "
};

const int iCsz=sizeof iceCream/sizeof*iceCream;

int main()
{
StringStack ss;
for(int i=0;i <iCsz;i++)
ss.push(&iceCream[i]);
const string* cp;
while((cp=ss.pop())!=0)
cout < <*cp < <endl;
}


[解决办法]
todototry说的没错，静态成员变量，必须这样使用