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struts配置有关问题,

2012-04-05 
struts配置问题,求助啊页面提交后老出现404问题,可能是很初级的问题了吧,找了很多老帖,各种修改各种无效,

struts配置问题,求助啊
页面提交后老出现404问题,可能是很初级的问题了吧,找了很多老帖,各种修改各种无效,大家帮帮忙吧
下面是源码:
login.jsp

Java code
<%@ page language="java" import="java.util.*" pageEncoding="GBK"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'login.jsp' starting page</title>        <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/css" href="styles.css">    -->  </head>    <body>    <form action="login.action" method="post"">        用户名:<input type="text" name="username"><br>        密码:<input type="password" name="password"><br>        <input type="submit" value="提交">    </form>  </body></html>

web.xml
XML code
<?xml version="1.0" encoding="UTF-8"?><web-app version="2.5"     xmlns="http://java.sun.com/xml/ns/javaee"     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee     http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">    <filter>        <filter-name>struts2</filter-name>        <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>    </filter>    <filter-mapping>        <filter-name>struts2</filter-name>        <url-pattern>/*</url-pattern>    </filter-mapping></web-app>

LoginAction.java
Java code
package com.test.action;public class LoginAction {    private String username;    private String password;    public String getUsername() {        return username;    }    public void setUsername(String username) {        this.username = username;    }        public String getPassword() {        return password;    }    public void setPassword(String password) {        this.password = password;    }    public String execute() throws Exception    {                return "success";    }}

result.jsp
Java code
<%@ page language="java" import="java.util.*" pageEncoding="GBK"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'result.jsp' starting page</title>        <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/css" href="styles.css">    -->  </head>    <body>      用户名:${requestScope.username }<br>      密码:${requestScope.password }<br>      </body></html> 


struts.xml
XML code
<?xml version="1.0" encoding="UTF-8" ?><!DOCTYPE struts PUBLIC    "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"    "http://struts.apache.org/dtds/struts-2.0.dtd"><struts>    <package name="struts2" extends="struts-default">        <action name="login" class="com.test.action.LoginAction">            <result name="success">/result.jsp</result>        </action>    </package></struts>

login提交后的错误提示:
HTTP Status 404 - /struts/login.action

--------------------------------------------

type Status report

message /struts/login.action

description The requested resource (/struts/login.action) is not available.


--------------------------------------------

Apache Tomcat/7.0.26

[解决办法]
好像还有一个配置文件吧?配置后缀的
告诉机器是通过.do还是.action访问你的Action

[解决办法]
第一个jsp页面没有把struts2引进来 程序不知道你要用struts2;




Java code
<%@ page language="java" pageEncoding="UTF-8"%><%@ taglib prefix="s" uri="/struts-tags"%>//使用相应的标签<%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'login.jsp' starting page</title>        <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/css" href="styles.css">    -->  </head>    <body>    <form action="login.action" method="post"">        用户名:<input type="text" name="username"><br>        密码:<input type="password" name="password"><br>        <input type="submit" value="提交">    </form>  </body></html>
[解决办法]
问题1:要继承struts2的ActionSupport
问题2: <filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.do</url-pattern>
</filter-mapping>
[解决办法]
你只要把action方法中的类继承Action,或者ActionSupport,就可以了.
[解决办法]
Java code
<s:form action="login" method="post"">      <s:textfield name="username" label="username"></s:textfield>       <s:password name="password" label="password"></s:password>         <s:submit label="submit"></s:submit> </s:form>
------解决方案--------------------


action类继承ActionSupport类
[解决办法]
你的程序里面没有那些标签啊

[解决办法]
我不同意楼上说的,不用struts2的标签完全可以,用户的最终POST请求和用不用struts2标签有什么区别?用了struts2标签POST请求参数有什么不同吗?
楼主错在LoginAction没有继承ActionSupport类,因此系统不认为LoginAction类可以执行,所以报找不到login.action错误
[解决办法]
加个绝度i路径吧 。 <form action="<%=basePath%>login.action" method="post"">
[解决办法]
你的路径问题!

/struts/login.action


你的struts配置文件的问题。好好检查下。
[解决办法]

Java code
public class LoginAction extends ActionSupport{
[解决办法]
Java code
 <action name="login" class="com.test.action.LoginAction">
[解决办法]
在页面为login.action,配置文件为login.do
1,改为统一的后缀
2,在struts.xml里配个常量为<constant name="struts.action.extension" value="action"/>
[解决办法]

Java code
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'index.jsp' starting page</title>    <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/css" href="styles.css">    -->  </head>    <body>    <form action="login.action" method="post">      用户名:<input type="text" name="username"><br>      密  码:<input type="password" name="password"><br>     <input type="submit" value="提交">    </form>  </body></html>
[解决办法]
tomcat错误提示:
/struts/login.action

description The requested resource (/struts/login.action) is not available.
大概意思应该是没有找到请求描述资源(/struts/login.action)
楼主你仔细看看你的路径或者是包路径什么的 配置对不对
[解决办法]
初看没什么错误 

建议楼主加上namespace=“/”配置项

在<package name="struts2" extends="struts-default">里面

[解决办法]
最好别用login,user之类的词命名action...
[解决办法]
404应该是路径问题吧,仔细看下路径问题。。。
[解决办法]
先说几个无关紧要的
1.<form action="login.action" method="post""> 你这个多了个引号


2.既然在web.xml中配置拦截方式是/* 那么login.action中的.action不加也可以的


建议action继承ActionSupport

Java code
package com.test.action;import com.opensymphony.xwork2.ActionSupport;public class LoginAction extends ActionSupport {    private String username;    private String password;        public void setUsername(String username) {        this.username = username;    }    public void setPassword(String password) {        this.password = password;    }    @Override    public String execute() throws Exception {        return SUCCESS;    }}
[解决办法]
<form action="login.action" method="post"">
用户名:<input type="text" name="username"><br>
密码:<input type="password" name="password"><br>
<input type="submit" value="提交">
</form>
把login.action的action 去掉试试···

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