十六进制转换成字符解决办法

十六进制转换成字符
如 char ch[] = { 0xE8, 0x03 };

现在要把 ch[0] ch[1] 变成字符串 为"E8" "03" 应怎样转换？
 


[解决办法]
举个一个字符的例子：
char c = 0xE8;
char sz[3] = {0};
sz[0] = ((c & 0xF0) >> 4) & 0x0F; //取高四位,最后 & 0x0F是为了防止逻辑右移时自动在前面补充1
sz[1] = (c & 0x0F);//取低四位


[解决办法]
printf("%02X", (unsigned char)ch[0]);
[解决办法]

C/C++ code

char ch[2] = { 0xE8, 0x03 };char chhexstr[2][5];sprintf(chhexstr[0],"0x%02x",(unsigned char)ch[0]);sprintf(chhexstr[1],"0x%02x",(unsigned char)ch[1]);printf("%s,%s\n",chhexstr[0],chhexstr[1]);