LINUX 管道通信有关问题

LINUX 管道通信问题
本人刚刚接触这些，不太懂，话说LINUX 的库函数 应该有 SDK吧？ 在哪。。类似 MSDN 样的。。。
话不多说 直接上代码

C/C++ code

#include <sys/types.h>#include <sys/stat.h>#include <errno.h>#include <fcntl.h>#include <stdio.h>#include <stdlib.h>#include <string.h>#define FIFO "/myfifo"int main(int argc, char** argv){    int fd;    char w_buf[100];    int nwrite;    if(fd == -1)    {        if(errno == ENXIO)        {            printf("open error; no reading process\n");        }    }        fd = open(FIFO,O_WRONLY|O_NONBLOCK,0);    strcpy(w_buf,"1111111111111111111111111111111111");    if((nwrite = write(fd,w_buf,100)) == -1)    {         printf("write wrong: %d \n",nwrite);        if(errno == EAGAIN)        {            printf("The FIFO has not been read yet,Please try later\n");        }    }else    {        printf("write %s to the FIFO \n",w_buf);    }    return 1;}

write(fd,w_buf,100)) 返回值总是 -1 坐等高手解答

[解决办法]
if(fd == -1)
{
if(errno == ENXIO)
{
printf("open error; no reading process\n");
}
}

fd = open(FIFO,O_WRONLY|O_NONBLOCK,0);

这两段颠倒了吧，先open，再判断
[解决办法]
fd = open(FIFO,O_WRONLY|O_NONBLOCK,0);
if(fd == -1)
{
perror("open");
printf("open wrong: %d \n",fd);
if(errno == ENXIO)
{
printf("open error; no reading process\n");
}
}

[解决办法]
查看open失败原因

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