C++ 中【没有合适的默认构造函数可用】和【类块放在main后面】的疑惑。该怎么解决

C++ 中【没有合适的默认构造函数可用】和【类块放在main后面】的疑惑。

C/C++ code

#include "stdafx.h"using namespace std;/* --- --- --- --- --- --- --- 武器类 --- --- --- --- --- --- */class Weapon{private:    string name;    int power;public:    void Show();    //Weapon(){};    Weapon(string name,int power);};Weapon::Weapon(string name, int power){    this->name = name;    this->power = power;};void Weapon::Show(){    cout<<"武器名："<<this->name<<"威力值："<<this->power<<endl;};/* --- --- --- --- --- --- --- 角色类 --- --- --- --- --- --- */class Actor{private:    string name;    bool gender;    Weapon weapon;public:    Actor(string name, bool gender);    void Say();    void Say(string message);    void SetWeapon(Weapon &weapon)    {        this->weapon = weapon;    }};Actor::Actor(string name, bool gender){    this->gender = gender;    this->name = name;}void Actor::Say(){    cout<<"我乃"<<this->name<<"是也..."<<endl;};void Actor::Say(string message){    cout<<this->name<<"："<<message<<endl;};/* --- --- --- --- --- --- --- MAIN --- --- --- --- --- --- */int main(){    Weapon* weapon = new Weapon("九环锡杖",20);    Actor* tang = new Actor("唐三藏", 1);    tang->SetWeapon(*weapon);    tang->Say();    tang->Say("Only you...伴我去西经");    weapon->Show();    cin.get();    return 0;};

Q1：为什么注释掉Weapon的void构造函数会提示error C2512: “Weapon”: 没有合适的默认构造函数可用。

Q2：我把Weapon和Actor两个类放到main后面，并且在main前像“声明函数”（书上叫函数的原型）：
class Actor;class Weapon;
编译器却给了我一大堆错误？(VS2008)


[解决办法]
Q1的问题出在你的角色类里私有成员weapon，当你创建Actor对象时，一定会为其所有成员构造。此时的weapon成员必须调用默认构造函数.如果你不声明，肯定会报错的啊
[解决办法]
1、由于你在Weapon中定义了其他构造函数，那么，编译器不会为你创建默认构造函数；然而，你在Actor的构造函数中没有调用Weapon的构造函数，那么，编译器会调用Weapon的默认构造函数，然而，却没有定义，所以，产生了“error C2512: “Weapon”: 没有合适的默认构造函数可用”错误！
[解决办法]
2、如果将类的定义放在使用代码的后面，那么使用代码使用的方式必须是引用、指针，否则，编译器不知道为其分配多少内存。
也就是说，如果使用一个类的对象，该类的定义是必须可见的。
[解决办法]
1.你已经声明了构造函数,则编译器不会再为你默认合成构造函数了.
所以注释掉Weapon的void构造函数自然不可以.


[解决办法]
Q2：我把Weapon和Actor两个类放到main后面，并且在main前像“声明函数”（书上叫函数的原型）： 
class Actor;class Weapon; 

把你所谓的声明.,贴出来看下.
[解决办法]
我不知道你理解的类的声明是什么样的,但是像下面这样写,肯定是可以的.
class Weapon
{
private:
string name;
int power;
public:
void Show();
Weapon(){};
Weapon(string name,int power);
};

这样一整块都是声明来的(如果你写过头文件,肯定知道)

C/C++ code

/* --- --- --- --- --- --- --- 武器类 --- --- --- --- --- --- */class Weapon{private:    string name;    int power;public:    void Show();    Weapon(){};    Weapon(string name,int power);};/* --- --- --- --- --- --- --- 角色类 --- --- --- --- --- --- */class Actor{private:    string name;    bool gender;    Weapon weapon;public:    Actor(string name, bool gender);    void Say();    void Say(string message);    void SetWeapon(Weapon &weapon)    {        this->weapon = weapon;    }};/* --- --- --- --- --- --- --- MAIN --- --- --- --- --- --- */int main(){    Weapon* weapon = new Weapon("九环锡杖",20);    Actor* tang = new Actor("唐三藏", 1);    tang->SetWeapon(*weapon);    tang->Say();    tang->Say("Only you...伴我去西经");    weapon->Show();    cin.get();    return 0;};Weapon::Weapon(string name, int power){    this->name = name;    this->power = power;};void Weapon::Show(){    cout<<"武器名："<<this->name<<"威力值："<<this->power<<endl;};Actor::Actor(string name, bool gender){    this->gender = gender;    this->name = name;}void Actor::Say(){    cout<<"我乃"<<this->name<<"是也..."<<endl;};void Actor::Say(string message){    cout<<this->name<<"："<<message<<endl;}; 
 
[解决办法]
2楼都说了。或者你什么也不定义，全用set
[解决办法]
mark,学习了
[解决办法]
探讨

C/C++ codeclass Weapon;
class Actor;
int main()
{
    //and so on....
}

class Weapon
{
    //and so on....
}

class Actor
{
    //and so on....
}



这样是错的。正确声明应该是？？
 

 

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