这个结构的XML文件，怎么序列化

这个结构的XML文件，如何序列化
RT, Value的节点数量不确定。

XML code

  <Measurement Name="SpdupPlinqVs1">    <value>100</value>    <value>110</value>    <value>120</value>  </Measurement>

C# code

[XmlRootAttribute("Measurement")]public class MeasurementResult{    [NonSerialized]    private string measurementName = "";    [NonSerialized]    private List<string> valueList = new List<string>();    public MeasurementResult()    {     }    [XmlAttribute("Name")]    public string MeasurementName    {        get        {            return measurementName;        }        set        {            measurementName = value;        }    }    [XmlArrayItem("value")]    public List<string> ValueList    {        get        {            return valueList;        }        set        {            valueList.Clear();            if (value != null)            {                valueList.AddRange(value);            }        }    }}private void Serialize(){    string filePath = "e:\\111111.xml";    MeasurementResult result = new MeasurementResult();    result.MeasurementName = "test";    result.ValueList.AddRange(new string[] { "1", "2", "3" });    XmlSerializer mySerializer = new XmlSerializer(typeof(MeasurementResult));    StreamWriter myWriter = new StreamWriter(filePath);    XmlSerializerNamespaces xmlns = new XmlSerializerNamespaces();    xmlns.Add(String.Empty, String.Empty);    mySerializer.Serialize(myWriter, result, xmlns);    myWriter.Close();}private MeasurementResult Deserialize(){    string filePath = "e:\\111111.xml";    XmlSerializer mySerializer = new XmlSerializer(typeof(MeasurementResult));    FileStream myFileStream = new FileStream(filePath, FileMode.Open);    MeasurementResult result = mySerializer.Deserialize(myFileStream) as MeasurementResult;    myFileStream.Close();    return result;}