首页 诗词 字典 板报 句子 名言 友答 励志 学校 网站地图
当前位置: 首页 > 教程频道 > 网站开发 > PHP >

snoopy模拟登录为何无法登录解决办法

2012-03-25 
snoopy模拟登录为何无法登录自己写的要登录的系统PHP codeHTMl headmeta http-equivcontent-type

snoopy模拟登录为何无法登录
自己写的要登录的系统

PHP code
<HTMl> <head><meta http-equiv="content-type" content="text/html; charset=utf-8" /></head> <title>testlogin</title> <BODY><br /><CENTER>testlogin</CENTER><br />    <form name="login" method="post" action="verifyLogin.php">  <table align="center">    <tr>  <td>id:</td>  <td><input type="text" name="loginId"></td>  </tr>    <tr>  <td>pass:</td>  <td><input type="password" name="loginPass"></td>  </tr>  </table>    <br /><CENTER><input type="submit" name="loginSubmit" value ="submit"></CENTER>  </form> </BODY></HTML>


PHP code
<?php$loginId = $_POST['loginId'];$loginPass = $_POST['loginPass'];if($loginId == "aaa" && $loginPass == "123")  echo "welcome!";else  echo "<script language=javascript>alert('fail!');window.location='login.php'</script>"; ?>


snoopy模拟登录代码
PHP code
<HTML> <HEAD>  <TITLE> New Document </TITLE> </HEAD> <BODY><?phpinclude "Snoopy.class.php";$snoopy = new Snoopy;$submit_url = "http://127.0.0.1/testlogin/login.php"; $submit_vars["loginId"] = "aaa"; //可以登录的密码为aaa,123$submit_vars["loginPass"] = "123";//$submit_vars["loginSubmit"] = "登陆";$snoopy->submit($submit_url,$submit_vars);echo $snoopy->results;?> </BODY></HTML>


问题1:上面的代码无法登录,哪里出了问题呢,我的php环境是简捷包appserv-win32-2.5.10,参数默认

[解决办法]
注意你的<form name="login" method="post" action="verifyLogin.php">
action链接与
$snoopy->submit($submit_url,$submit_vars);$submit_url链接一致.

热点排行