一元二次方程！c++的收藏起来哈！该如何解决

一元二次方程！！！！c++的收藏起来哈！！
//*********************************************
//RootConstructor.cpp
#include <iostream>
#include <cmath>
using namespace std;

class RootConstructor
{
private:
  int a,b,c;
  double x1,x2;
public:
 RootConstructor(int i,int j,int k)
 {
  a=i; b=j; c=k;
  x1=(-b+sqrt(b*b-4*a*c))/(2*a);
  x2=(-b-sqrt(b*b-4*a*c))/(2*a);
 } 
 void disp()
 {
  cout<<"您输入的方程是：\n";
  cout<<a<<"x^2";

  if (b>0)
  cout <<"+" <<b <<"x";
  else
  cout<<b <<"x";

  if (c>0)
  cout<<"+"<<c<<"=0";
  else
  cout<<c<<"=0";

  cout<<"\n下面是方程的根：\n";
  cout <<"x1=" <<x1 <<endl;
  cout <<"x2=" <<x2 <<endl;
 }
};

int main()
{
 RootConstructor objS(1,-5,6);
 objS.disp();
 return 0;
}

//*********************************************

[解决办法]

C/C++ code

//*********************************************//RootConstructor.cpp#include <iostream>#include <cmath>using namespace std;class RootConstructor {private:    double a,b,c;    double x1,x2;public:    RootConstructor(double i,double j,double k) {        a=i; b=j; c=k;        if (b*b-4*a*c<0.000001) {            x1=0.0;            x2=0.0;        } else {            x1=(-b+sqrt(b*b-4.0*a*c))/(2.0*a);            x2=(-b-sqrt(b*b-4.0*a*c))/(2.0*a);        }    }    void roots() {        cout<<"您输入的方程是：\n";        cout<<a<<"x^2";        if (b<-0.000001)            cout<< b <<"x";        else if (0.000001<b)            cout<< "+"<< b <<"x";        if (c<-0.000001)            cout<< c <<"=0";        else if (0.000001<c)            cout<< "+"<< c <<"=0";        if (x1==0.0 && x2==0.0) {            cout<<"\n此方程无解。\n";        } else {            cout<<"\n下面是方程的根：\n";            cout <<"x1=" <<x1 <<endl;            cout <<"x2=" <<x2 <<endl;        }    }};int main() {    RootConstructor equation(1.0,-5.0,6.0);    equation.roots();    return 0;}//*********************************************
[解决办法]
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引用:

C/C++ code
//*********************************************
//RootConstructor.cpp
#include <iostream>
#include <cmath>
using namespace std;

class RootConstructor {
p……