char[]转为string
#include <string>
#include <iostream>
#include <stdio.h>
using namespace std;
void DeciToBin(short decimal,char bintemp[]);
int main()
{
short d = 30043;
char bintemp[16];
char a[5]= "abc ";
DeciToBin(d,bintemp);
string str = bintemp;
cout < <str < <endl;
return 0;
}
void DeciToBin(short decimal,char bintemp[])
{
int count = 15;
for(int i=0;i <16;i++)
bintemp[i] = 0;
while(decimal> 0)
{
bintemp[count]=decimal%2;
decimal=decimal/2;
count--;
}
}
为什么str = a;输出的就是abc，str = bintemp输出就为空？
我该如何将bintemp转换成str（转换过程中，不能用itoa函数）
[解决办法]
#include "string "
#include "iostream "
#include "stdio.h "
#include "math.h "
using namespace std;
int DeciToBin(int decimal, double *bintemp);
int main()
{
int d = 30043;
char *bintemp;
double bin = 0;
int binLen = DeciToBin(d, &bin);
bintemp = (char *)malloc(binLen + 128);
memset(bintemp, 0 , binLen + 128);
for(int i =0; i < binLen; i++)
{
double exp = pow(10.0, binLen -1 -i);
int tmpBin = (int)(bin/exp);
bin -= (double)tmpBin * exp;
bintemp[i] = tmpBin + '0 ';
}
string str = bintemp;
cout < <str < <endl;
free(bintemp);
return 0;
}
int DeciToBin(int decimal, double *bintemp)
{
int count = 0;
double exp;
if (_set_SSE2_enable(1))
printf( "SSE2 enabled.\n ");
else
printf( "SSE2 not enabled; processor does not support SSE2.\n ");
while(decimal> 0)
{
exp = pow(10.0, count);
*bintemp +=((decimal%2) *exp);
decimal = decimal/2;
count++;
}
return count;
}
----------------------------
给分
