怎样将一个数三位三位的输出,该怎么解决

怎样将一个数三位三位的输出
比如我有一个数为123456789
现在我要将它输出为123.456.789.怎么输出？

[解决办法]

C/C++ code

#include <stdio.h>void show(unsigned int val){    if(val == 0)        return;    show(val/1000);        val = val%1000;    printf("%d.",val);}int main(){    unsigned int val = 123456789;        show(val);}
[解决办法]
C/C++ code
#include <iostream>#include <string>using namespace std;int main() {    char *buff;    int lenth = sprintf(buff, "%d", 123456789);    cout << buff << endl;    string s(buff, lenth);    for(int i = 1, j = 0; 3 * i <= lenth; i++, j++) //[color=#FF0000]j[/color]因为string对象的长度随插入“.”增加        s.insert(i * 3 + j, ".");    cout << s << endl;            return 0;}
[解决办法]
int temp = 0;
           for (int i = 100; i <= 1000; i++)
           {
               temp++;
               if (temp % 3 == 0)
               {
                   Console.WriteLine(temp.ToString());
               }
           }
           Console.Read();
[解决办法]
[code=C/C++][
#include <stdio.h>
#include<iostream.h>
#include<malloc.h>
typedef struct SNode//结构体定义链栈
{
int data;
SNode *next;
}*Lstack;
void init(Lstack &s)//初始化
{
s=NULL;
}
void push(Lstack &s,int e)//进栈
{
Lstack p;
p=new SNode;
p->data=e;
p->next=s;
s=p;
}
bool pop(Lstack &s,int &e)//出栈
{
Lstack p;
if(!s) return false;
e=s->data;
p=s;
s=s->next;
delete p;
return true;
}
void show(unsigned int val)
{
Lstack p;
int m;
init(p);
while(1)
{
if(val == 0)
break;
else
{
push(p,val%1000);
val=val/1000;
}
}
   while(pop(p,m))
{
cout<<m<<'.';
}
}

int main()
{
   unsigned int val = 123456789;
  
   show(val);
return 0;
}

/code]