模板函数find这样做为什么有错，该怎么解决！！！！！！！！！！！！
struct PERSONINFO
{
int OnLine;
char UserId[10];
bool operator==(const PERSONINFO & rhs)const
{
return ( OnLine == rhs.OnLine && UserId == rhs.UserId);
}
};
PERSONINFO pInfo ;
pInfo.OnLine = 3;
strcpy( pInfo.UserId , "a " );
m_list.push_back(pInfo);
pInfo.OnLine = 4;
strcpy( pInfo.UserId , "b " );
m_list.push_back(pInfo);
pInfo.OnLine = 1;
strcpy( pInfo.UserId , "c " );
m_list.push_back(pInfo);
PERSONINFO Info ;
Info.OnLine = 3;
strcpy( Info.UserId , "a " );
list <PERSONINFO> ::iterator it_;
it_ = find(m_list.begin(), m_list.end(), &Info);
报错：d:\microsoft visual studio\vc98\include\algorithm(43) : error C2678: binary '== ' : no operator defined which takes a left-hand operand of type 'struct PERSONINFO ' (or there is no acceptable conversion)
E:\SortList\SortListDlg.cpp(258) : see reference to function template instantiation 'class std::list <struct PERSONINFO,class std::allocator <struct PERSONINFO> > ::iterator __cdecl std::find(class std::list <struct PERSONINFO,class std::allocat
or <struct PERSONINFO> > ::iterator,class std::list <struct PERSONINFO,class std::allocator <struct PERSONINFO> > ::iterator,struct PERSONINFO *const & ) ' being compiled
[解决办法]
it_ = find(m_list.begin(), m_list.end(), Info);
[解决办法]
编译器说得很清楚了，需要的是二元的operator==,把operator==要么独立出来做成友元，要么做成静态的试试
