c简单问题，帮帮忙。。。。。
输入3个整数，然后显示这3个整数的和，平均数，积，最小数和最大数。
用IF单一选择形式编写。。
我编写的：
#include "stdio.h "
int main()
{
int x, y, z;
printf( "Input three different integers: ");
scanf( "%d%d%d ", &x, &y, &z );
printf( "Sum is %d\n ", x + y + z );
printf( "Average is %d\n ", (x+y+z)/3 );
printf( "Product is %d\n ", x * y * z );
if(x <y,y <z){
printf( "Smallest is %d\n ", x );
printf( "Largest is %d\n ", z );
}
if(y <z <x){
printf( "Smallest is %d\n ", y );
printf( "Largest is %d\n ", x );
}
if(z <x <y){
printf( "Smallest is %d\n ", z );
printf( "Largest is %d\n ", y );
}
if(x <z <y){
printf( "Smallest is %d\n ", x );
printf( "Largest is %d\n ", y );
}
if(y <x <z){
printf( "Smallest is %d\n ", y );
printf( "Largest is %d\n ", z );
}
if(z <y <x){
printf( "Smallest is %d\n ", z );
printf( "Largest is %d\n ", x );
}
return 0;
}
运行结果显示
无论输入哪3个数，6个if语句后面的printf（）个个都显示出来
我都不想要这样的结果
我到底哪里错了，程序怎么不判断条件的？？
哪位能指出来我的错误，并且编写个例子出来。。。
拜托，拜托。。不胜感激！
[解决办法]
#include "stdio.h "
int main()
{
int x, y, z;
printf( "Input three different integers: ");
scanf( "%d%d%d ", &x, &y, &z );
printf( "Sum is %d\n ", x + y + z );
printf( "Average is %d\n ", (x+y+z)/3 );
printf( "Product is %d\n ", x * y * z );
if(x <y && y <z){
printf( "Smallest is %d\n ", x );
printf( "Largest is %d\n ", z );
}
if(y <z && z <x){
printf( "Smallest is %d\n ", y );
printf( "Largest is %d\n ", x );
}
if(z <x && x <y){
printf( "Smallest is %d\n ", z );
printf( "Largest is %d\n ", y );
if(y <z && z <x){
printf( "Smallest is %d\n ", y );
printf( "Largest is %d\n ", x );
}
if(z <x && x <y){
printf( "Smallest is %d\n ", z );
printf( "Largest is %d\n ", y );
}
if(x <z && z <y){
printf( "Smallest is %d\n ", x );
printf( "Largest is %d\n ", y );
}
if(y <x && x <z){
printf( "Smallest is %d\n ", y );
printf( "Largest is %d\n ", z );
}
if(z <y && y <x){
printf( "Smallest is %d\n ", z );
printf( "Largest is %d\n ", x );
}
return 0;
}
这样就行了
