我这条sql语句写的对么 感觉好像不对
查出c-ip列的个数(去掉重复),同时要保证sc-status列的值必须为200,同时还要保证cs(Referer)列的结尾必须为html或者htm
我的写法如下
select COUNT(distinct c-ip) from 表A where sc-status=200 and cs(Referer) like '%.html' or cs(Referer) like '%.htm'
select COUNT(distinct c-ip) from 表A where sc-status=200 and ([cs(Referer)] like '%.html' or [cs(Referer)] like '%.htm')
[解决办法]
select COUNT(distinct c-ip) from 表A where (sc-status=200 or sc-status=60)and ([cs(Referer)] like '%.html' or [cs(Referer)] like '%.htm')--orselect COUNT(distinct c-ip) from 表A where sc-status in (200,60)and ([cs(Referer)] like '%.html' or [cs(Referer)] like '%.htm')
[解决办法]
select COUNT(distinct c-ip) from 表A where sc-status in (200,60)and ([cs(Referer)] like '%.html' or [cs(Referer)] like '%.htm'