C# 泛型集合序列化和反序列化问题
各位高手，请指定一下，我这个是用Udp协议做的通信程序，现在时发送和接收泛型集合，发送没问题，接收的时候不知道怎么反序列化？？？？报的错是“没有对象“201326592”的映射。”，原因好像是序列化后没有反回来吧！！
/发送数据
public void SendData()
{
try
{
//定义对方主机和端口
IPEndPoint ipPoint = new IPEndPoint(IPAddress.Parse(txtHisIP.Text), int.Parse(txtHisPort.Text));
//实例化并赋值
Users user = new Users();
user.Name = txtName.Text.Trim();
user.Sex = txtSex.Text.Trim();
user.Age = int.Parse(txtAge.Text.Trim());
user.Address = txtAddress.Text.Trim();
user.Phone = ulong.Parse(txtPhone.Text.Trim());
user.Content = txtContent.Text.Trim();
List<Users> list = new List<Users>();
list.Add(user);
//序列化集合
FileStream fs = new FileStream("C:\\go.txt", FileMode.Open); //定义一个文件流
BinaryFormatter bf = new BinaryFormatter(); //二进制方式
bf.Serialize(fs, list); //序列化保存配置文件对象list
fs.Seek(0, SeekOrigin.Begin);
string ss = "";
//读取出来
using (StreamReader sr = new StreamReader(fs))
{
ss = sr.ReadToEnd();
sr.Close();
}
#region 类序列化
////类序列化
//xml = new XmlSerializer(typeof(Users));
//ms = new MemoryStream();
//xml.Serialize(ms, user);
//ms.Seek(0, SeekOrigin.Begin); //将当前流的位置设为指定值
//string str = Encoding.UTF8.GetString(ms.ToArray());
#endregion
//string to byte[]
byte[] by = Encoding.UTF8.GetBytes(ss);
//发送
udpClient.Send(by, by.Length, ipPoint);
toolsStatus.Text = "已发送！";
fs.Close(); //关闭流
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
接收：
//接收任何地址的数据 接收
IPEndPoint point = new IPEndPoint(IPAddress.Any, 0);
//接收数据，储存在byte数组里
byte[] bytes = udpClient.Receive(ref point);
//byte to string
string str = Encoding.UTF8.GetString(bytes); //乱码问题
//反序列化集合
FileStream fs = new FileStream("F:\\go.txt", FileMode.Create);
using (StreamWriter sw = new StreamWriter(fs))
{
sw.Write(str); //写入
sw.Close();
}
fs.Close();
FileStream fsf = new FileStream("F:\\go.txt", FileMode.Open);
BinaryFormatter bf = new BinaryFormatter();
List<Users> list = bf.Deserialize(fsf) as List<Users>; //获取
[解决办法]
http://www.cnblogs.com/lindping/archive/2011/01/15/2004836.html
------解决方案--------------------
你发送和读取，用string读取都是错误的。
1. 序列化之后的 byte[] 应该直接Send ，保存用 System.IO.File.WriteAllBytes 保存二进制数据文件
而不用做任何编码转换。
2. 读取的话也是直接用 byte[] 转成 MemoryStream 然后反序列化
//读取出来
using (StreamReader sr = new StreamReader(fs))
{
ss = sr.ReadToEnd();
sr.Close();
}
...
byte[] bytes = udpClient.Receive(ref point);
//byte to string
string str = Encoding.UTF8.GetString(bytes); //乱码问题
//反序列化集合
FileStream fs = new FileStream("F:\\go.txt", FileMode.Create);
[解决办法]
首先你的Users对象必须是再Client端和Server端共享的DLL来的，而且要可序列化，根据你的问题我建了三个Project：
1.ClassLibrary1.dll,放User class，在Client端和Server都同时引用它。
[Serializable]
public class Users
{
public int Age { get; set; }
public string Name { get; set; }
public object Sex { get; set; }
public object Address { get; set; }
public ulong Phone { get; set; }
public object Content { get; set; }
}
2.client project
class Program
{
private static UdpClient udpClient;
static void Main(string[] args)
{
udpClient = new UdpClient();
SendData();
Console.Read();
}
public static void SendData()
{
try
{
//定义对方主机和端口
IPEndPoint ipPoint = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9800);
//实例化并赋值
Users user = new Users
{
Name = "test",
Sex = "1",
Age = 27,
Address = "127.0.0.1",
Phone = 13698756236,
Content = "test"
};
List<Users> list = new List<Users>();
list.Add(user);
//序列化集合
Stream s = new MemoryStream();
BinaryFormatter bf = new BinaryFormatter(); //二进制方式
bf.Serialize(s, list); //序列化保存配置文件对象list
byte[] by = new byte[s.Length];
s.Position = 0;
s.Read(by, 0, by.Length);
//发送
udpClient.Send(by, by.Length, ipPoint);
Console.WriteLine("success!~");
}
catch (Exception ex)
{
Console.WriteLine(ex.ToString());
}
}
}
3.Server：
class Program
{
private static UdpClient udpClient;
static void Main(string[] args)
{
udpClient = new UdpClient(9800); //这里Server端的监听端口必须是Client发送的端口
ReceiveData();
Console.Read();
}
private static void ReceiveData()
{
IPEndPoint point = new IPEndPoint(IPAddress.Any, 0);
//接收数据，储存在byte数组里
byte[] bytes = udpClient.Receive(ref point);
Stream s = new MemoryStream(bytes);
BinaryFormatter bf = new BinaryFormatter();
List<Users> list = bf.Deserialize(s) as List<Users>; //获取
Console.WriteLine(list[0].Name + " >> " + list[0].Address);
}
}
[解决办法]
private void 序列号ToolStripMenuItem_Click(object sender, EventArgs e)
{
//将对象序列化到文件中去
//创建文件流对象
FileStream fs = new FileStream("data.dat", FileMode.OpenOrCreate, FileAccess.Write);
//创建格式化器(序列化器);
BinaryFormatter bf = new BinaryFormatter();
//进行序列化或反序列化操作
bf.Serialize(fs, ManagerHelper.School);
fs.Close();
}
private void 反序列化ToolStripMenuItem_Click(object sender, EventArgs e)
{
//创建文件流对象
FileStream fs = new FileStream("data.dat", FileMode.Open, FileAccess.Read);
//创建格式化器(序列化器);
BinaryFormatter bf = new BinaryFormatter();
//进行序列化或反序列化操作
SortedList obj = (SortedList)bf.Deserialize(fs);
fs.Close();
ManagerHelper.School = obj;
}
