50分只给一人。
以下程序中static定义的静态变量还是弄不清他是怎么起作用的，麻烦各位说的简明点。
#include <stdio.h>
#include <stdlib.h>
int n=1;
void func()
{
static int x=4;int y=10;
x+=2;
n+=10;
y+=n;
printf ( "FUNC :x=%2d y=%2d n=%2d\n ",x,y,n);
}
int main()
{
static int x=5;
int y;
y=n;
printf ( "MAIN :x=%2d y=%2d n=%2d\n ",x,y,n);
func();
printf ( "MAIN :x=%2d y=%2d n=%2d\n ",x,y,n);
func();
system ( "PAUSE ");
return 0;
}
[解决办法]
1.printf ( "MAIN :x=%2d y=%2d n=%2d\n ",x,y,n);
输出5 1 1没问题吧
2,printf ( "FUNC :x=%2d y=%2d n=%2d\n ",x,y,n);
x=4+2=6，n=n+10==1+10=11,y=y+n==10+11=21
所以输出6 21 11
3，printf ( "MAIN :x=%2d y=%2d n=%2d\n ",x,y,n);
这里x还是main里的x，当然还是5，y还是main里的y，当然还是1，n已经在fun函数里i改变成为11
所以输出5 1 11
4，printf ( "FUNC :x=%2d y=%2d n=%2d\n ",x,y,n);
x是static的，所以x是fun函数内部的x，已经为6，然后重复第二步的操作
x=6+2=8，n=n+10==11+10=21,y=y+n==10+21=31
所以输出8 31 21
要注意函数里的y不是static的
