关于鼠标悬浮在td上，即更换表格错误，谢谢！
想实现鼠标悬浮在“显示11”上，则id为11的table可见，id为22的table不可见！~
<html>
<head>
</head>
<body>
<script language= "javascript ">
function showaa(par)
{
document.getElementById( "11 ").style.display = "none ";
document.getElementById( "22 ").style.display = "none ";
document.getElementByID(par).style.display = " ";
}
</script>
<table border= "1 " width= "40px ">
<tr>
<td onmouseover= 'showadv( "11 ") '> 显示11 </td>
<td onmouseover= 'showadv( "22 ") '> 显示22 </td>
</table>
<table id= "11 " border= "1 " width= "200px " style= "display: ">
<tr> <td> 这个是11 </td> </tr>
</table>
<table id= "22 " border= "1 " width= "200px " style= "Display:none ">
<tr> <td> 这个是22 </td> </tr>
</table>
</body
</html>
[解决办法]
不要用数字做为id开头.
function showaa(obj1, obj2)
{
document.getElementById(obj1).style.display = "none ";
document.getElementById(obj2).style.display = " ";
}
