急请大家帮忙看看如何用C++编写一个自行车里程表的程序，谢谢！
要准备考试，室友mm求助我这道题，我也不懂~~~只能请大家帮忙了，多谢哈！
问题是要设计一个类来实现一个自行车里程兼测速计，简称为bikemeter,其性质如下：
bikemeter每秒钟都会从内部时钟inter_clock接收到时钟信号tick()，并且伴随着车轮每转一圈，轮轴上一个传感器会将信号click()传给bikemeter（相当于是两个计数器counter，一个用来计时一个用来计车轮转的圈数）。
在车轮转动时，会将轮的直径diameter告诉bikemeter。从以上这些信息，bikemeter就能够计算出其他信息，如当前速度current_speed，行驶距离distance以及平均速度average_speed。 同样的，bikemeter在每一个 "trip "(程序中会出现这个东西的定义，欧不知道啥米意思)开始前，可以被归零reset.
下面给的框架程序中，main()调用函数和bikemeter类去测试这个类bikemeter.在constructer中应该存放着车轮的直径diameter，单位为inch，可以设默认值为27。在行驶过程中，bikemeter会收到一系列的穿插着click和tick的信号，每一个click（）代表着车轮转了一圈，每一个tick()代表着时钟走过一秒。因此，假设收到的一系列信号为
click(),click(),tick(),click(),click(),click(),tick(),click(),tick(),click(),tick(),click(),tick(),tick(),click(),click(),tick(),click().
那么在每一秒间隔内车轮转的圈数click()分别为：2,3,1,1,1,0,2. 在最后一个click后跟的是没有写出来的tick)。那么，在这么多秒内，行驶的距离为每秒内圈数之和*车轮的直径，圈数之和为2+3+1+1+1+0+2=10，直径为27 inch，那么距离即为10*27*pi(pi的值为3.14159)，所经过的时间为7个tick()，即为7秒，那么平均速度average_speed即为10/7圈。
对于速度，要求bikemeter是以英里miles为单位的，表达为miles/hour，且每一秒，即每一个tick()时都要显示出当前速度speed, 即实时更新。为了知道实时的speed，要求采用的方法是知道每次最近4秒钟内的车轮转圈数click（） 's。如前面的一系列信号，知道了7秒内的总圈数为10，前三秒内的圈数为2+3+1=6，则最近4个tick内的圈数为10-6=4圈，即这段时间内的click数为4。求最近4秒内的速度即为每秒显示的实时speed。
最后，框架程序还要比较两个bikemeter的累计行驶距离，利用逻辑操作符 <, <=,> ,> =,==以及!=， 如假设a的累计行驶距离比b大，那么bikemeter a > bikemeter b（是要在bikemeter的类中用操作符重载么？我瞎猜的~）
程序要求：完成class bikemeter的相关结构体和函数，并于框架程序结合起来，形成一个完整的程序，并经过主函数中的测试函数测试，能够正确运行
这是已给出的框架程序，
void ride(bikemeter &a, int trip[], int ct);
void mainTest();
void logicalOpsTest();
int main(){
cout < < "Test out the bikemeter class\n ";
mainTest();
logicalOpsTest();
cout < < "End of program\n ";
}
void logicalOpsTest(){
bikemeter a,b;
int trip[]={5,3,2,9,8,2,5,3,6,7};
ride(a,trip,9);
ride(b,trip,10);
cout < < "\n We compare two bikemeters by comparing their distances\n ";
cout < <a < < " <\n " < <b < < ": " < <(a <b) < <endl;
cout < <a < < " > \n " < <b < < ": " < <(a> b) < <endl;
cout < <a < < " <=\n " < <b < < ": " < <(a <=b) < <endl;
cout < <a < < " > =\n " < <b < < ": " < <(a> =b) < <endl;
cout < <a < < " ==\n " < <b < < ": " < <(a==b) < <endl;
cout < <a < < " !=\n " < <b < < ": " < <(a!=b) < <endl;
a.reset();
ride(a,trip,10);
cout < <a < < " <\n " < <b < < ": " < <(a <b) < <endl;
cout < <a < < " > \n " < <b < < ": " < <(a> b) < <endl;
cout < <a < < " <=\n " < <b < < ": " < <(a <=b) < <endl;
cout < <a < < " > =\n " < <b < < ": " < <(a> =b) < <endl;
cout < <a < < " ==\n " < <b < < ": " < <(a==b) < <endl;
cout < <a < < " !=\n " < <b < < ": " < <(a!=b) < <endl;
}
void mainTest(){
bikemeter a(26.5);
b;
int trip[]={5,3,2,9,8,2,5,3,6,7};
ride(a,trip,10);
ride(b,trip,10);
cout < < "For the following 'trip '\n "
< < "second #of clicks\n ";
for(int j=0;j <10;j++)
{
cout.width(5);
cout < <(j+1);
cout.width(10);
cout < <trip[j] < <endl;
}
cout < < "For 26.5 inch tire: \n " < <a
< < "\nFor a 27 inch tire: \n " < <b < <endl;
//Now test the copy constructor
bikemeter c(a);
cout < < "The two bikemeters below should be the same\n " < <a < <endl < <c < <endl;
}
void ride(bikemeter & a, int trip[], int ct){
for(int sec=0;sec <ct;sec++)
{
for (int t=0; t <trip[sec];t++)
a.click();
a.tick();
}
}
可模仿下面的计数器class Counter来完成class bikemeter，也可直接将class Counter用于上面的程序和类的设计中，但要求不能改动class Counter内的代码。
# include <iostream>
using namespace std;
class Counter{
public:
static const int MAX=1000;
Counter(); //a counter with count==0
Counter(int k); //a counter with count==k, but if k <0, crash
Counter(const Counter &c);// a counter with the contents of c
~Counter();//nothing much to kill off in this case
void reset(int k=0); //set the count to k. if k <= or k> MAX,crash
int GetCount()const; //return the count
Counter & inc(); //increment the count by one, if the count exceeds
//MAX then crash, return a reference to the counter
Counter & operator+=(int k); //precondition: k> 0
//current count+k <=MAX
//postcondition:count incremented by k
// if precondition are not satisfied,
//crash
//return a reference to the counter
Counter operator+(const Counter & c);//precondition: sum of counts;
//on self and c is <=MAX;
//postcondition: return a new
//counter with sum of counts on
//old counters, crash if
//precondition not met
friend Counter operator*(const Counter &a, const Counter &b);
//precondition: sum of counts
//on a and b is <=MAX
//postcondition:return a new
//counter with product of counts
//on old counters. Crash if
//preconditions not met
//Display the contents of the counters as [ <count> ]
friend ostream & operator < <(ostream &out,const Counter &c);
static void test();
private:
int count;
static void check(bool b,char *mess);
};
void Counter::test(){
Counter a,b(20),c(b);
b.inc().inc();
cout < <a < <b < <c < <endl;
a.reset(9);
cout < <a < <endl;
cout < < "The count on the counter is " < <a.getCount() < <endl;
(a+=2)+=3;
cout < < "Now we should have 14: " < <a < <endl;
cout < <a < < " + " < <b < < " == " < <(a+b) < <endl;
cout < <a < < " + " < <3 < < " == " < <(a+3) < <endl;
cout < <a < < " * " < <b < < " == " < <(a*b) < <endl;
cout < <a < < " * " < <3 < < " == " < <(a*3) < <endl;
}
Counter::Counter(){
reset();
}
Counter::Counter(int k){
reset(k);
}
Counter:: Counter(const Counter &c):count(c.count){}
Counter::~Counter(){
cout < < "Killing off a counter with count == " < <count < <endl;
}
void Counter::reset(int k){
check(k> =0 && k <=MAX, "(reset()) reset value out of range ");
count=k;
}
int Counter::getCount()const{return count;}
Counter & Counter::inc(){
count++;
check(count <=MAX, "(inc()) counter overflow ");
return *this;
}
Counter & Counter::operator+=(int k){
check(k> 0, "(+=) increment must be positive ");
return *this;
}
Counter Counter::operator+(const Counter & c){
return Counter(count+c.count);
}
Counter operator*(const Counter &a, const Counter &b){
return Counter(a.count*b.count);
}
ostream & operator < <(ostream &out, const Counter &c){
out < < "[ " < <c.count < < "] ";
return out;
}
void Counter::check(bool b, char *mess){
if(!b){
cerr < < "ERROR[Counter]: " < <mess < <endl;
exit(1);
}
}
[解决办法]
..........这么多
