一个cout的用法解决方案

一个cout的用法
是c++   primer上的，如下：
ilist_item   *it   =   mylist.find(   8   );

cout   < <   "\n "
< <   "Searching   for   the   value   8:   found   it < < "
< <   (   it   < <   "   yes!\n "   :   "   no!\n "   );

最下面一句话编译错误啊，大家帮看看什么问题
“ < <   (   it   < <   "   yes!\n "   :   "   no!\n "   );”

[解决办法]
对不起,上面的说错了.应该是这样:
cout < < "\n "
< < "Searching for the value 8: found it < < "
< < ( it? "yes!\n " : " no!\n ") ;