分期收款的视图,如何建立?在线等
表:
stallid,costName,startdate,closedate,costtime,preday ,costprice
表数据如下
房号 费用类型 合同开始 合同截止 收费周期(月单位 ) 提前天数 金额
5F0001租金 2007-01-01 2008-12-31 12 5 40000
5F0003租金 2007-03-20 2008-11-19 6 5 20000
5F0004租金 2007-05-08 2009-04-31 3 5 60000
5F0006租金 2007-02-03 2007-08-02 2 5 40000
希望得到视图
stallid,costName,coststart,costclose,paydate,payvalue
房号 费用类型 费用开始 费用截止 应收日期 应收金额
5F0001租金 2007-01-01 2007-12-31 2007-01-01 20000
5F0001租金 2008-01-01 2008-12-31 2007-12-27 20000
5F0003租金 2007-03-20 2007-09-19 2007-03-20 6000
5F0003租金 2007-09-20 2008-03-19 2008-03-15 6000
5F0003租金 2008-03-20 2008-09-19 2008-03-15 6000
5F0003租金 2008-09-20 2008-11-19 2008-03-15 2000
......
依次类推,如何建立每期收款视图.
函数 用来计算两个日期相差月份,可以直接调用.
create function uf_GetMonthdiff(@startdate datetime,@closedate datetime)
returns int
as
begin
declare @r int
set @r=datediff(month,@startdate,@closedate)-1
declare @s datetime
set @s=dateadd(month,@r,@startdate)
while dateadd(month,1,@s)<@closedate
begin
set @s=dateadd(month,1,@s)
set @r=@r+1
end
if datediff(day,@s,@closedate)>15
set @r=@r+1
return @r
end
SELECT dbo.uf_GetMonthdiff('2007-03-20','2008-12-31') 得到21个月
[解决办法]
create table ta(房号 varchar(10),费用类型 varchar(6),合同开始 datetime,合同截止 datetime,收费周期 int,提前天数 int,金额 int)insert ta select'5F0001','租金','2007-01-01','2008-12-31',12,5 , 40000 union select '5F0003','租金','2007-03-20','2008-11-19',6,5 , 20000 union select '5F0004','租金','2007-05-08','2009-04-30',3,5 , 60000 union select '5F0006','租金','2007-02-03','2007-08-02',2,5 , 40000 goselect top 20 pid = identity(int,0,1) into # from sysobjects a,sysobjects bselect 房号 ,费用类型,合同开始 = dateadd(mm,a.收费周期*pid,a.合同开始),合同截止 = dateadd(mm,a.收费周期*(pid+1),a.合同开始),应收日期 = case when pid = 0 then 合同开始 else dateadd(d,- 提前天数 ,dateadd(mm,a.收费周期*(pid+1),a.合同开始)) endfrom ta aleft join # c on dateadd(mm,a.收费周期*pid,a.合同开始) < =a.合同截止/*房号 费用类型 合同开始 合同截止 应收日期 ---------- ------ ------------------------------------------------------ ------------------------------------------------------ ------------------------------------------------------ 5F0001 租金 2007-01-01 00:00:00.000 2008-01-01 00:00:00.000 2007-01-01 00:00:00.0005F0001 租金 2008-01-01 00:00:00.000 2009-01-01 00:00:00.000 2008-12-27 00:00:00.0005F0003 租金 2007-03-20 00:00:00.000 2007-09-20 00:00:00.000 2007-03-20 00:00:00.0005F0003 租金 2007-09-20 00:00:00.000 2008-03-20 00:00:00.000 2008-03-15 00:00:00.0005F0003 租金 2008-03-20 00:00:00.000 2008-09-20 00:00:00.000 2008-09-15 00:00:00.0005F0003 租金 2008-09-20 00:00:00.000 2009-03-20 00:00:00.000 2009-03-15 00:00:00.0005F0004 租金 2007-05-08 00:00:00.000 2007-08-08 00:00:00.000 2007-05-08 00:00:00.0005F0004 租金 2007-08-08 00:00:00.000 2007-11-08 00:00:00.000 2007-11-03 00:00:00.0005F0004 租金 2007-11-08 00:00:00.000 2008-02-08 00:00:00.000 2008-02-03 00:00:00.0005F0004 租金 2008-02-08 00:00:00.000 2008-05-08 00:00:00.000 2008-05-03 00:00:00.0005F0004 租金 2008-05-08 00:00:00.000 2008-08-08 00:00:00.000 2008-08-03 00:00:00.0005F0004 租金 2008-08-08 00:00:00.000 2008-11-08 00:00:00.000 2008-11-03 00:00:00.0005F0004 租金 2008-11-08 00:00:00.000 2009-02-08 00:00:00.000 2009-02-03 00:00:00.0005F0004 租金 2009-02-08 00:00:00.000 2009-05-08 00:00:00.000 2009-05-03 00:00:00.0005F0006 租金 2007-02-03 00:00:00.000 2007-04-03 00:00:00.000 2007-02-03 00:00:00.0005F0006 租金 2007-04-03 00:00:00.000 2007-06-03 00:00:00.000 2007-05-29 00:00:00.0005F0006 租金 2007-06-03 00:00:00.000 2007-08-03 00:00:00.000 2007-07-29 00:00:00.000*/drop table ta,#
[解决办法]
不是正好
create table ta(房号 varchar(10),费用类型 varchar(6),合同开始 datetime,合同截止 datetime,收费周期 int,提前天数 int,金额 int)insert ta select'5F0001','租金','2007-01-01','2008-12-31',12,5 , 40000 union select '5F0003','租金','2007-03-20','2008-11-19',6,5 , 20000 union select '5F0004','租金','2007-05-08','2009-04-30',3,5 , 60000 union select '5F0006','租金','2007-02-03','2007-08-02',2,5 , 40000 goselect top 20 pid = identity(int,0,1) into # from sysobjects a,sysobjects bselect 房号 ,费用类型,合同开始 = convert(char(10),dateadd(mm,a.收费周期*pid,a.合同开始),120),合同截止 = convert(char(10),dateadd(mm,a.收费周期*(pid+1),a.合同开始),120),应收日期 = convert(char(10),case when pid = 0 then 合同开始 else dateadd(d,- 提前天数 ,dateadd(mm,a.收费周期*(pid+1),a.合同开始)) end,120),收费周期 ,提前天数,应收金额 = case when round(金额 / ((datediff(mm,合同开始,合同截止)+1) / 收费周期 ) -400,-3)*(pid +1)< 金额 then round(金额 / ((datediff(mm,合同开始,合同截止)+1) / 收费周期 ) -400,-3) else 金额 - round(金额 / ((datediff(mm,合同开始,合同截止)+1) / 收费周期 ) -400,-3)*(pid ) endfrom ta aleft join # c on dateadd(mm,a.收费周期*pid,a.合同开始) < =a.合同截止/*房号 费用类型 合同开始 合同截止 应收日期 收费周期 提前天数 应收金额 ---------- ------ ---------- ---------- ---------- ----------- ----------- ----------- 5F0001 租金 2007-01-01 2008-01-01 2007-01-01 12 5 200005F0001 租金 2008-01-01 2009-01-01 2008-12-27 12 5 200005F0003 租金 2007-03-20 2007-09-20 2007-03-20 6 5 60005F0003 租金 2007-09-20 2008-03-20 2008-03-15 6 5 60005F0003 租金 2008-03-20 2008-09-20 2008-09-15 6 5 60005F0003 租金 2008-09-20 2009-03-20 2009-03-15 6 5 20005F0004 租金 2007-05-08 2007-08-08 2007-05-08 3 5 70005F0004 租金 2007-08-08 2007-11-08 2007-11-03 3 5 70005F0004 租金 2007-11-08 2008-02-08 2008-02-03 3 5 70005F0004 租金 2008-02-08 2008-05-08 2008-05-03 3 5 70005F0004 租金 2008-05-08 2008-08-08 2008-08-03 3 5 70005F0004 租金 2008-08-08 2008-11-08 2008-11-03 3 5 70005F0004 租金 2008-11-08 2009-02-08 2009-02-03 3 5 70005F0004 租金 2009-02-08 2009-05-08 2009-05-03 3 5 70005F0006 租金 2007-02-03 2007-04-03 2007-02-03 2 5 130005F0006 租金 2007-04-03 2007-06-03 2007-05-29 2 5 130005F0006 租金 2007-06-03 2007-08-03 2007-07-29 2 5 13000（所影响的行数为 17 行）*/drop table ta,#
