问一个分组的问题销售表A,有字段sale_date, employee_id,client_id,product_id,内容如下20100302 001C1 P1
问一个分组的问题
销售表A,有字段sale_date, employee_id,client_id,product_id,内容如下
20100302 001 C1 P1
20100302 001 C1 P2
20100302 002 C1 P1
20100302 002 C2 P1
20100302 002 C2 P2
20100302 003 C1 P1
现在需要把一天中，一个销售人员对一个客户卖出两种以上货物的纪录打印出来，如何实现？结果如下：
20100302 001 C1 P1
20100302 001 C1 P2
20100302 002 C2 P1
20100302 002 C2 P2
[解决办法]
select * from (
select sale_date,
employee_id,
client_id,
product_id,
count(1) over(partition by sale_date, employee_id, client_id) as cn
from a) where cn>1
前提是一个人卖一个客户一个产品两件的话，在库里存储要有数量
[解决办法]
- SQL code
with tmp as (select to_date('20100302','yyyymmdd') sale_date, '001' employee_id, 'C1' client_id, 'P1' product_id from dualunion allselect to_date('20100302','yyyymmdd') sale_date, '001' employee_id, 'C1' client_id, 'P2' product_id from dualunion allselect to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dualunion allselect to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C2' client_id, 'P1' product_id from dualunion allselect to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C2' client_id, 'P2' product_id from dualunion allselect to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual) select mt.sale_date,mt.employee_id,mt.client_id,mt.product_idfrom tmp mt,(select sale_date,employee_id,client_id,count(distinct product_id)from tmpgroup by sale_date,employee_id,client_idhaving count(distinct product_id) > 1) stwhere mt.sale_date = st.sale_dateand mt.employee_id = st.employee_idand mt.client_id = st.client_id;
[解决办法]
select *
from A
where (sale_date, employee_id,client_id) in
(select sale_date, employee_id,client_id
from A
group by sale_date, employee_id,client_id
having count(*)>1)
[解决办法]
分区查？over是什么意思？
不懂，帮顶 我也想知道如何弄...
[解决办法]
1.2.3楼都对！
但是1楼好！效率要高些！
[解决办法]
- SQL code
create table a(sale_date date,employee_id char(4),client_id char(4),product_id char(4));insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '001', 'C1', 'P1');insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '001', 'C1', 'P2');insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C2', 'P1');insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C2', 'P2');insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');SELECT to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_id, count(a1.product_id) product_countFROM a a1GROUP BY to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_idHAVING COUNT(a1.product_id)>=2;
[解决办法]
- SQL code
SQL> edi已写入 file afiedt.buf 1 select to_char(sale_date,'yyyymmdd') sale_date,employee_id,client_id,product_id from 2 tb a where exists(select 1 from tb where employee_id=a.employee_id and client_id=a.client_id 3 group by employee_id,client_id 4* having count(1)>=2)SQL> /SALE_DAT EMPLO CLIEN PRODU-------- ----- ----- -----20100302 001 c1 p120100302 001 c1 p220100302 002 c2 p120100302 002 c2 p2
[解决办法]
- SQL code
CREATE TABLE a(sale_date DATE,employee_id CHAR(4),client_id CHAR(4),product_id CHAR(4));INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P1');INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P2');INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P1');INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P2');INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');SELECT to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_idFROM a a1WHERE EXISTS (SELECT to_char(a2.sale_date,'yyyymmdd'), a2.employee_id, a2.client_id FROM a a2 WHERE to_char(a2.sale_date,'yyyymmdd')=to_char(a1.sale_date,'yyyymmdd') AND a2.employee_id= a1.employee_id AND a2.client_id=a1.client_id GROUP BY to_char(a2.sale_date,'yyyymmdd'), a2.employee_id, a2.client_id HAVING COUNT(DISTINCT a2.product_id)>=2 );
[解决办法]
- SQL code
CREATE TABLE a(
sale_date DATE,
employee_id CHAR(4),
client_id CHAR(4),
product_id CHAR(4)
);
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P2');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P2');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');
SELECT to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_id
FROM a a1
WHERE EXISTS (SELECT 1
FROM a a2
WHERE to_char(a2.sale_date,'yyyymmdd')=to_char(a1.sale_date,'yyyymmdd')
AND a2.employee_id= a1.employee_id
AND a2.client_id=a1.client_id
GROUP BY to_char(a2.sale_date,'yyyymmdd'), a2.employee_id, a2.client_id
HAVING COUNT(DISTINCT a2.product_id)>=2 );
-- 我是来蹭分的！
[解决办法]
-- 请注意：两种以上货物
-- 是“两种”，而不是“两件”！
[解决办法]
select sale_date, employee_id,client_id,product_id from A where exists (
select * from A as B where B.sale_date=A.sale_date and
B.employee_id=A.employee_id and B.client_id=A.client_id and
B.product_id<>A.product_id
)
[解决办法]
1L的正点
[解决办法]
接分ing
[解决办法]
- SQL code
--练习一下--1.with tt as ( select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P1' product_id from dual union all select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P2' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P1' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P2' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual ) SELECT sale_date, employee_id, client_id, product_id FROM (SELECT a.*, COUNT(1) over(PARTITION BY sale_date, employee_id, client_id) cn FROM (SELECT DISTINCT sale_date, employee_id, client_id, product_id FROM tt) a) WHERE cn > 1;--2.with tt as ( select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P1' product_id from dual union all select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P2' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P1' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P2' product_id from dual union all select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual ) SELECT a.* FROM tt a, (SELECT sale_date, employee_id, client_id FROM (SELECT DISTINCT sale_date, employee_id, client_id, product_id FROM tt) GROUP BY sale_date, employee_id, client_id HAVING COUNT(1) > 1) b WHERE a.sale_date = b.sale_date AND a.employee_id = b.employee_id AND a.client_id = b.client_id;
[解决办法]
- SQL code
select sale_date, employee_id,client_id,product_id,from tb awhere exists (select 1 from tb b where b.employee_id = a.employee_id and a.client_id = b.client_id group by sale_date,employee_id having count(1)>=2);
[解决办法]
看了下，楼主是说2种，不是2件。
所以having count(1) 这种写法是不对的，
having count(disintct product_id) 这种写法才对。