C++中子类怎么选择父类的构造函数

C++中子类如何选择父类的构造函数?class A{public:A(){coutA}A(int i){couta}}class B{public:

C++中子类如何选择父类的构造函数?
class A
{
public:
  A()
  {
  cout<<"A";
  }
  A(int i)
  {
  cout<<"a";
  }
};

class B
{
public:
  B()
  {
  cout<<"B";
  }
  B(int i)
  {
  cout<<"b";
  }
};

class C:public A
{
public:
  C()
  {
  cout<<"C";
  }

private:
  B m_temp;
};

int main()
{
  C test; //在这里,程序将输出"ABC"。如果我想输出"abC",该怎么做呢?向各位求教。
}


[解决办法]

C/C++ code
class C:public A { public:     C()     {         cout <<"C";     }     C(int a):A(a),m_temp(a)     {         cout <<"C";     }private:     B m_temp; }; int main() {     C test(1);         //    return 0;}
[解决办法]
up!

也可以不用继承了,都用聚合
class C:public A 

public:
C():m_tempA(),m_tempB()
{
cout < <"C"; 
}
C(int i):m_tempA(i),m_tempB(i) 

cout < <"C"; 


private: 
A m_tempA;
B m_tempB; 
};
int main() 

C test1; //输出"ABC"
C test2(1); //输出"abC"
}