为什么这题运行不来？
题目：利用命令行参数输出一月份到十二月份的英文名。
#include "stdio.h "
#include "stdlib.h "
#include "math.h "
int getmonth(char *str);
char *month_str[]={ "jan ", "feb ", "mar ", "apr ", "may ", "jun ", "jul ",
"aug ", "sep ", "oct ", "nov ", "dec "};
void main(int argc,char *argv[])
{
int k;
k=getmonth(argv[1]);
printf( "%s\n ",month_str[k-1]);
}
int getmonth(char *str)
{int k;
k=atoi(str);
return k;
}
[解决办法]
12明显就不对了，顶多也是0-11
[解决办法]
有这么一句 month_str[k-1]
12肯定是可以的
还有我编译之后，程序运行时正常的
[root@AccessGrid Test]# more main.c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int getmonth(char *str);
char *month_str[]={ "jan ", "feb ", "mar ", "apr ", "may ", "jun ", "jul ",
"aug ", "sep ", "oct ", "nov ", "dec "};
void main(int argc,char *argv[])
{
int k;
k=getmonth(argv[1]);
printf( "%s\n ",month_str[k-1]);
}
int getmonth(char *str)
{int k;
k=atoi(str);
return k;
}
[root@AccessGrid Test]# ./month 12
dec
[root@AccessGrid Test]# [root@AccessGrid Test]# more main.c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int getmonth(char *str);
char *month_str[]={ "jan ", "feb ", "mar ", "apr ", "may ", "jun ", "jul ",
"aug ", "sep ", "oct ", "nov ", "dec "};
void main(int argc,char *argv[])
{
int k;
k=getmonth(argv[1]);
printf( "%s\n ",month_str[k-1]);
}
int getmonth(char *str)
{int k;
k=atoi(str);
return k;
}
[root@AccessGrid Test]# ./month 12
dec
[root@AccessGrid Test]# [root@AccessGrid Test]# more main.c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int getmonth(char *str);
char *month_str[]={ "jan ", "feb ", "mar ", "apr ", "may ", "jun ", "jul ",
"aug ", "sep ", "oct ", "nov ", "dec "};
void main(int argc,char *argv[])
{
int k;
k=getmonth(argv[1]);
printf( "%s\n ",month_str[k-1]);
}
int getmonth(char *str)
{int k;
k=atoi(str);
return k;
}
[root@AccessGrid Test]# ./month 12
dec
[root@AccessGrid Test]# ./month 5
may
[解决办法]
因为这句k=getmonth(argv[1]);
所以你在Dos命令下输入 month 3的话，argv[1]中就是month
[解决办法]
都ok啊，我保存为main.exe。在dos下运行main 1,结果jan, main 12结果 dec...
