学习做菜单 2008-4-25有这样一个 xml:?xml version1.0 encodingutf-8 ?MenuMenuNode Urlabc.
学习做菜单 2008-4-25
有这样一个 xml:
<?xml version="1.0" encoding="utf-8" ?>
<Menu>
<MenuNode Url="abc.html" NormalPath="abc.jpg" OverPath="abc_over.jpg" OnTips="产品" />
<MenuNode Url="def.html" NormalPath="def.jpg" OverPath="def_over.jpg" OnTips="新闻" />
<MenuNode Url="ghi.html" NormalPath="ghi.jpg" OverPath="ghi_over.jpg" OnTips="反馈" />
</Menu>
如何用 javascript 读取每一个<MenuNode>，并生成图片链接排列在页面上？
Url 表示链接指向的URL
NormalPath 表示正常状态下的图片
OverPath 表示鼠标移动到图片上的状态
OnTips 表示鼠标提示
50 分求助，谢谢。
[解决办法]
你自己把图片换上就可以了...
- JScript code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>Read XMLData</title><script type="text/javascript">var loadXML = function (path, callback) { if (window.ActiveXObject) { var xml = new window.ActiveXObject('Microsoft.XMLDOM'); xml.async = false; xml.load(path); callback(xml); } else if (document.implementation && document.implementation.createDocument) { var xml = document.implementation.createDocument("", "", null); xml.load(path); xml.onload = function () { callback(xml); }; }};window.onload = function () { loadXML('xml.xml', function (xml) { var datas = xml.getElementsByTagName('MenuNode'), htmls = [], i = 0, t, l; for (l = datas.length ; i < l ; i ++) { t = datas[i], htmls[htmls.length] = '<a href="' + t.getAttribute('Url') + '"><img src="' + t.getAttribute('NormalPath') + '" alt="' + t.getAttribute('OnTips') + '" onmouseover="this.src=\'' + t.getAttribute('OverPath') + '\'" onmouseout="this.src=\'' + t.getAttribute('NormalPath') + '\'" \/><\/a>'; } document.getElementById('data').innerHTML = htmls.join('<br \/>'); });};</script></head><body><div id="data"></div></body></html>