JS创建下拉框如何实现页面跳转
如下用JS创建下拉框后如何实现跳转：
<body >
<script type="text/javascript">
function createSelect()
{
var select1 = document.createElement("select");
var ooption = new Array();
ooption[0] = "one";
ooption[1] = "two";
ooption[2] = "three";
ooption[3] = "four";
ooption[4] = "five";
var optionValue = new Array();
optionValue[0] = "1.html";
optionValue[1] = "2.html";
optionValue[2] = "3.html";
optionValue[3] = "4.html";
optionValue[4] = "5.html";
for(var i=0;i<5;i++)
{
select1.options[i] = new Option(ooption[i], optionValue[i]);
}
document.body.appendChild(select1);
}
createSelect()
</script>
</body>
[解决办法]
select1.onchange = function(){
location.href = this.value;
}
[解决办法]
select1.onchange=function()
{
window.location.href=this.options[this.selectedIndex].value;
}
