九九乘法有点小错，麻烦帮我看一下
#include <stdio.h>
void main()
{
int a=1,b,num;
while (a <10)
{
b=1;
while (b <=a)
{
b++;
num=a*b;
printf( "%d*%d=%-5d ",a,b,num);
};
printf( "\n ");
a++;
}
}
[解决办法]
#include <stdio.h>
#include <stdlib.h>
int main()
{
int a=1,b,num;
while (a <10)
{
b=0;
while (b <a)
{
b++;
num=a*b;
printf( "%d*%d=%-5d ",a,b,num);
};
printf( "\n ");
a++;
}
system( "pause ");
}
[解决办法]
#include "stdafx.h "
#include <stdio.h>
int main(int argc, char* argv[])
{
int a=1,b,num;
while (a <10)
{
b=1;
while (b <=a)
{
num=a*b;
printf( "%d*%d=%-5d ",a,b,num);
b++;
};
printf( "\n ");
a++;
}
}
b++放在后面就OK！
[解决办法]
Result:
1*1=1
2*1=2 2*2=4
3*1=3 3*2=6 3*3=9
4*1=4 4*2=8 4*3=12 4*4=16
5*1=5 5*2=10 5*3=15 5*4=20 5*5=25
6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36
7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49
8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64
9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
[解决办法]
#include <stdio.h>
void main()
{
int a=1,b,num;
while (a <10)
{
b=1;
while (b <=a)
{
num=a*b;
printf( "%d*%d=%-5d ",a,b,num);
b++;//放在后面
};
printf( "\n ");
a++;
}
}
[解决办法]
正解
[解决办法]
#include <stdio.h>
void main()
{
int a=1,b;
while (a <=9)
{
b=1;
while(b <=a)
{
printf( "%d*%d=%d\t ",a,b,a*b);
b++;
}
printf( "\n ");
a++;
}
}
[解决办法]
#include <stdio.h>
void main()
{
int a=1,b;
while (a <=9)
{
b=1;
while(b <=a)
{
printf( "%d*%d=%d\t ",a,b,a*b);
b++;
}
printf( "\n ");
a++;
}
}
[解决办法]
楼主对的，
gjw310() 兄弟，你的就为好说了
