Linux下64位整数的使用有关问题

Linux下64位整数的使用问题
想在Linux(ubuntu kernel 2.6.21)下使用64位整数，有如下程序片断：

...
long long llNum = 0x1111222233334444; //(1)
...
printf("0x%x\n", llNum); //(2)
...

编译时提示(1)处"Warning: integer constant is too large for 'long' type"
运行(2)时显示0x33334444
即使把long long换成int64_t或者long long int也不行，到底怎样才能使用64位整数呢？


[解决办法]

C/C++ code

/*- * file: int64.c * auth: mymtom * date: 2008-08-19 */#include <sys/types.h>#include <stdio.h>intmain(void){        long long       nLL = 0x1111222233334444LL;        int64_t         n64 = 0x5555666677778888LL;        (void)printf("%llx\n", nLL);        (void)printf("%llx\n", n64);        return (0);}
[解决办法]
你用的就是64位，只不过你当32为打印出来。

要去掉warning:
man gcc
      -Wlong-long
          Warn if long long type is used.  This is default.  To inhibit the
          warning messages, use -Wno-long-long.  Flags -Wlong-long and
          -Wno-long-long are taken into account only when -pedantic flag is
          used.