解析ftp路径的有关问题

解析ftp路径的问题
一字符串格式为 usr:pwd@ip:path/file 我想把他们截取出来 分为5部分
程序写好了 编译通过 但是结果有问题....谁能帮我看看?或者给个answer...
我猜可能是我一些函数没用好 strncpy memccpy 之类的

#include <cstdlib>
#include <iostream>
#include <tchar.h>
#include <ctime>

#include <stdio.h>
#include <string.h>


char* ExtractName( char *fullname)
{
char* usr;
char* pwd;
char* ip;
char* path;
char* file;
 char* temp;
  char* name;
  int rpos = 0;
int lpos = 0;
name = fullname;
  char* dest;
  
  int at = -1;
  
  for(int ii =strlen(fullname)-1; ((ii > 0) && (at < 0)); ii--) //get pos of '@'
  {
  if (fullname[ii] == '@')
  { 
  at = ii;
  } 
  }
   
  int colon1 = -1;
  //get the first colon betweet usr & pwd
  for(int lpos = at-1; ((rpos > 0) && (colon1 < 0)); lpos--)
  {
  if(fullname[lpos] == ':')
  {
colon1 = lpos;  
  // get string of usr & pwd
  strncpy(usr,fullname,colon1-1);
usr[colon1] = '\0';
strchr(temp,':'); // string after first ':'
memccpy(pwd,temp,'@',at-lpos);


  }
  }  
   
  temp = strchr(temp, '@');//get the string after '@'
   
 int colon2 = -1;
 
 //get the second colon between ip & full path
 for(int rpos = strlen(temp)-1; ((rpos > 0) && (colon2 < 0)); rpos--)
  {
  if(fullname[rpos] == ':')
  {
colon2 = rpos;  
  strncpy(ip, temp, colon2-1);// get string of ip 
  ip[colon2] = '\0';
  temp = strchr(temp, ':'); //get the string of 'fullpath'
  }
  }
  int slash = -1;
  for (int jj=strlen(temp)-1; ((jj > 0 ) && (slash < 0)) ; jj--)//the pos of last '/'
  {
  if(fullname[jj] == '/') 
{
slash = jj;
strncpy(path, temp, slash); //get path
path[slash] = '\0';
  file = strrchr(temp,'/');
   

}
   
  }
  std::cout << usr << endl
  << path << endl;
}
   
  int main(int argc,char *argv[])  
  {  
  char* file1 = "kevin:pass@127.0.0.1:/var/path/kevin/demo.cpp" ;
  char* s = ExtractName(char* file1);
  printf("%s",s);


  }




[解决办法]
strchr(temp, ': '); // string after first ': ' 
memccpy(pwd,temp, '@ ',at-lpos); 
temp这时候还是一个野指针呢
[解决办法]

C/C++ code

#include<iostream>#include<algorithm>#include<string>#include<vector>using namespace std;int main(){    string str = "kevin:pass@127.0.0.1:/var/path/kevin/demo.cpp";    char token[4][3] = {":","@",":/"};    vector<string> sub_str;    int stpos = 0;    int endpos = 0;    int index = 0;    while(index<3)    {    endpos = str.find_first_of(token[index++],stpos);    sub_str.push_back(str.substr(stpos,endpos-stpos));    stpos = endpos+1;    }      //最后的"/"比较特殊，做特殊处理     endpos = str.find_last_of("/",string::npos);    sub_str.push_back(str.substr(stpos+1,endpos-stpos));        sub_str.push_back(str.substr(endpos+1,str.length()));    for(vector<string>::iterator it = sub_str.begin();it!=sub_str.end();++it)    cout<<*it<<endl;        getchar();    return 0;}