tcp socket通信 文件名和文件一起传输
遇到一个问题，client端和server端通过tcp socket传输图片，假设是本地文件test.png，我想把文件名和图片一起传输过去，试了很久，发现一直解码不正确，不知道该怎么办，小弟对io操作确实不是很熟悉，贴一下代码，求指点。
求高人指点啊，我也不知道我为什么只能给62分最高，本来应该给100分的，先感激不尽了。
Client端
public class Client {
private static final int PORT = 6666;
private static final String IP = "127.0.0.1";
private static String subject = "Floating";
private static String fileName = "test.png";
private static String filePath = "/Users/junxiyin/Desktop/"+fileName;
public static void main(String[] args){
OutputStream outputStream = null;
FileInputStream fis = null;
try{
Socket s = new Socket(IP, PORT);
fis = new FileInputStream(filePath);
outputStream = s.getOutputStream();
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(outputStream));
StringBuffer sb = new StringBuffer();
sb.append(fileName + "/n/joshua");
byte[] buffer = new byte[8192]; //建立一个buffer，将数据暂时存储，避免多次读写硬盘
int temp = 0 ;
while((temp = fis.read(buffer))!= -1){ //从inputStream读取数据并将其存储在buffer中
sb.append(new String(buffer,0,temp));
}
bw.write(sb.toString());
System.out.println("from the client " + sb.toString());
fis.close();
bw.flush();
bw.close();
s.close();
} catch (Exception e) {
e.printStackTrace();
}
}
}
Server端
public class Server {
public static void main(String[] args){
InputStream is = null;
BufferedReader br = null;
String temp = null;
OutputStream os = null;
StringBuffer str = new StringBuffer();
try {
ServerSocket ss = new ServerSocket(6666);
Socket s = ss.accept();
is = s.getInputStream();
br = new BufferedReader(new InputStreamReader(is));
while((temp = br.readLine()) != null){
str.append(temp);
}
String[] strDest = str.toString().split("/n/joshua");
if(strDest.length != 2)
System.err.println("error: strDest.length != 2");
System.out.println(strDest.length);
// fileName
System.out.println("fileName: " + strDest[0]);
// file
System.out.println("file: " + strDest[1]);
File file = new File("/Users/junxiyin/Desktop/testCopy.png");
os = new FileOutputStream(file);
os.write(strDest[2].getBytes());
os.flush();
os.close();
is.close();
s.close();
}catch (IOException e) {
e.printStackTrace();
}
}
}
[解决办法]
分开传好一些。
[解决办法]
String[] strDest = str.toString().split("/n/joshua");
这肯定有问题的，str.toString一是编码不确定，一是你怎么保证图片字节流中不包含joshua的编码。
好点的办法是：
自己定义一个包的格式：
比如从前到后，
2B:包总长
1B:文件名长
XB:文件名数据
YB:图片数据
其中B表示字节，XB表示文件名实际长度，YB表示图片数据长度
[解决办法]
传输图片 不应该用字符流啊~~~应该是用字节流
[解决办法]
给你抄点代码，大体是2楼那个意思。
定义个结构，先传文件名长度，通过这个长度取文件名，再得到开始下载的文件偏移量。
资源下载:http://download.csdn.net/detail/AFer198215/3647106
服务器端:
- Java code
public class DownloadResponsetHandler extends ResponsetHandler{ private static final Logger logger = Logger.getLogger(DownloadResponsetHandler.class); public void process() throws Exception { byte[] buffer = new byte[512]; int readLen = 0; RandomAccessFile fileIn = null; //4,这个数必需小512 int fileNameSize = 0; //int(n) String fileName = null; //8 long startPosit = 0; readLen = read(buffer, 0, 4); if(4 > readLen){ logger.error("数据错误."); return; } fileNameSize = Utility.byte2Int(buffer,0); readLen = read(buffer, 0, fileNameSize); if(fileNameSize > readLen){ logger.error("数据错误."); return; } fileName = new String(buffer, 0, fileNameSize, RequestCommand.CHARSET_ENCODING); readLen = read(buffer, 0, 8); if(8 > readLen){ logger.error("数据错误."); return; } startPosit = Utility.byte2Long(buffer,0); try{ fileIn = new RandomAccessFile(fileName, "r"); fileIn.seek(startPosit); while(-1 != (readLen = fileIn.read(buffer))){ write(buffer,0,readLen); } }finally{ try{ if(null != fileIn) fileIn.close(); }catch(Exception ex){ } } logger.debug("发送数据完成."); } }