windows FTP 命令行,是否能够将上传的路径作为一个参数传递给执行命令呢
---opftp.bat
ftp -s:test.txt
---test.txt
open218.206.93.226
0179upload
aye63h
bin
mkdir floder1
mput C:\f\*.bmp
y
y
bye
如上;
因为 floder1 , C:\f\*.bmp
这两个地方都可能发生变化,哪位兄弟知道,怎么能从外部将这两个信息动态的
变化呢；
还是根本不支持;只能够写程序动态变化；
谢谢!
[解决办法]
用echo 动态写test.txt 吧
[解决办法]
连长正解，在opftp.bat中用echo命令动态生成test.txt
@echo off
echo Please input your target folder name:
set /p TarDir=
echo Please input your files:
set /p TarFile=
echo open218.206.93.226> test.txt
echo 0179upload> > test.txt
echo aye63h> > test.txt
echo bin> > test.txt
echo mkdir %TarDir%> > test.txt
echo mput %TarFile%> > test.txt
echo y> > test.txt
echo y> > test.txt
echo bye> > test.txt
rem ftp -s:test.txt
[解决办法]
@echo off
echo Please input your target folder name:
set /p TarDir=
echo Please input your files:
set /p TarFile=
echo open218.206.93.226> test.txt
echo 0179upload> > test.txt
echo aye63h> > test.txt
echo bin> > test.txt
echo mkdir %TarDir%> > test.txt
echo mput %TarFile%> > test.txt
echo y> > test.txt
echo y> > test.txt
echo bye> > test.txt
ftp -s:test.txt
