复杂一点的left join有关问题

复杂一点的left join问题
SELECT           Dish.DishID,   DishImage.ImagePath,   Dish.DishName
FROM                   Dish   LEFT   OUTER   JOIN
                                            DishImage   ON   Dish.DishID   =   DishImage.DishID
WHERE           (Dish.Online   =   1)

查询结果

9       /9/s10042007171459.jpg                   DishName5
10     /10/s10042007171705.jpg                 Honey   Roast   Pork
11     /11/s10042007171801.jpg                 Curry   Chicken
12     /12/s10042007171918.jpg                 Pork   with   Onions   and   Ginger
12     /12/s10042007172007.jpg                 Pork   with   Onions   and   Ginger
13     /13/s05042007164747.jpg                 Crispy   Chilli   Beef
14     /14/s10042007172237.jpg                 DishName14
15     NULL                                                           Egg   Fried   Rice

（所影响的行数为   11   行）

能不能相同id的只显示一条记录呢，我只想要一个图片而已，比如  

9       /9/s10042007171459.jpg                   DishName5
10     /10/s10042007171705.jpg                 Honey   Roast   Pork
11     /11/s10042007171801.jpg                 Curry   Chicken
12     /12/s10042007171918.jpg                 Pork   with   Onions   and   Ginger
13     /13/s05042007164747.jpg                 Crispy   Chilli   Beef
14     /14/s10042007172237.jpg                 DishName14
15     NULL                                                           Egg   Fried   Rice

谢谢

[解决办法]
SELECT Dish.DishID, max(DishImage.ImagePath), max(Dish.DishName)
FROM Dish LEFT OUTER JOIN
DishImage ON Dish.DishID = DishImage.DishID
WHERE (Dish.Online = 1)
group by Dish.DishID
[解决办法]
一、加一distinct:
SELECT distinct Dish.DishID, DishImage.ImagePath, Dish.DishName
FROM Dish LEFT OUTER JOIN
DishImage ON Dish.DishID = DishImage.DishID
WHERE (Dish.Online = 1)

[解决办法]
同意：gjz_1209(龙行天下－－结婚好累！)
------解决方案--------------------

SELECT distinct Dish.DishID,DishImage.ImagePath,Dish,Dish.DishName
FROM Dish LEFT OUTER JOIN
DishImage ON Dish.DishID = DishImage.DishID
WHERE (Dish.Online = 1)