Exception in thread "main" java.lang.NullPointerException,该怎么处理

Exception in thread "main" java.lang.NullPointerException
谁帮我分析分析，我是新手

import javax.swing.JOptionPane;

public class Demo2 {
class Mpoint{
double x,y;
Mpoint(){}
void getX(){
String input1 = JOptionPane.showInputDialog("x坐标：");
x = Double.parseDouble(input1);
x = 45;
}
void getY(){
String input2 = JOptionPane.showInputDialog("y坐标：");
y = Double.parseDouble(input2);
}
}

public static void main(String[] args){
int n = 0;
Mpoint p1 = null;
do{
String input=
JOptionPane.showInputDialog("1:x"+'\n'+"2:y"+'\n'+"3:退出");
n = Integer.parseInt(input);
switch(n){
case 1:
p1.getX();
case 2:
p1.getY();
case 3:
break;
}

}while(n<3);

}

}

[解决办法]
Mpoint p1 = null;问题在这句话上。。。没有创建对象 肯定是Nullpointer
[解决办法]

Java code

import javax.swing.JOptionPane;class Mpoint{double x,y;Mpoint(){}void getX(){String input1 = JOptionPane.showInputDialog("x坐标：");x = Double.parseDouble(input1);System.out.println(x);//x = 45;}void getY(){String input2 = JOptionPane.showInputDialog("y坐标：");y = Double.parseDouble(input2);System.out.println(y);}}public class Test4 {public static void main(String[] args){int n = 0;Mpoint p1 = new Mpoint();do{String input=JOptionPane.showInputDialog("1:x"+'\n'+"2:y"+'\n'+"3:退出");n = Integer.parseInt(input);System.out.println(n);switch(n){case 1:p1.getX();case 2:p1.getY();case 3:break;}}while(n<3);}}