js中的invoke 疑问??
if(typeof Webdisk == "undefined ") Webdisk={};
if(typeof Webdisk.reg == "undefined ") Webdisk.reg={};
Webdisk.reg_class = function() {};
Object.extend(Webdisk.reg_class.prototype, Object.extend(new AjaxPro.AjaxClass(), {
check: function(username) {
return this.invoke( "check ", { "username ":username}, this.check.getArguments().slice(1));
},
RegUser: function(team, username, password, uquestion, uanswer, email, sex, url, qq, msn, realname, phone, address, company, bm, recommend, tjuser, ValidateCode, curr) {
return this.invoke( "RegUser ", { "team ":team, "username ":username, "password ":password, "uquestion ":uquestion, "uanswer ":uanswer, "email ":email, "sex ":sex, "url ":url, "qq ":qq, "msn ":msn, "realname ":realname, "phone ":phone, "address ":address, "company ":company, "bm ":bm, "recommend ":recommend, "tjuser ":tjuser, "ValidateCode ":ValidateCode, "curr ":curr}, this.RegUser.getArguments().slice(19));
},
url: '/ajaxpro/Webdisk.reg,Webdisk.ashx '
}));
Webdisk.reg = new Webdisk.reg_class();
-------------
其中的 return this.invoke( "check ", .... 是什么意思? 是调用服务器上的check方法吗???
[解决办法]
又一个被 prototype.js 毒害的同志。你的 Webdisk.reg_class 是从 AjaxPro.AjaxClass 类继承下来的，你自己去这个脚本文件里看吧！
