如何读取xml文件并显示成表格模式
请教各位如何读取xml文件并显示成表格模式，因本人刚学delphi，所以请各位说详细点，最好有代码和注解，请各位高手多多指教，不胜感激！
xml文件如下：
<?xml version= "1.0 " encoding= "GB2312 "?>
<Product xmlns:xsi= "http://www.w3.org/2001/XMLSchema-instance " xsi:noNamespaceSchemaLocation= "DataStat.xsd ">
<Env Ver= "100 " DisDate= "2007-03-23 "/>
<ActTable Title= "排名 " BranchNumber= "5 " Stocknumber= "20 " Unit= "万元,% " RecNum= "1 ">
<SubTitle> 排名A </SubTitle>
<Date CName= "交易日期 "> 2007-03-23 </Date>
<BeginTime CName= "开始时间 "> 09:30:00 </BeginTime>
<EndTime CName= "结束时间 "> 10:00:00 </EndTime>
<Record>
<Id> 1 </Id>
<Name> 名称A </Name>
<TradeValue> 1097.40 </TradeValue>
<Turnover> 283.64 </Turnover>
<SubRecord>
<Type> 收入 </Type>
<Branch>
<Id> 1 </Id>
<Name> 名称A-1 </Name>
<Total> 72250.33 </Total>
</Branch>
<Branch>
<Id> 2 </Id>
<Name> 名称A-2 </Name>
<Total> 58002.48 </Total>
</Branch>
<SubRecord>
<Type> 支出 </Type>
<Branch>
<Id> 1 </Id>
<Name> 名称A-3 </Name>
<Total> 73549.71 </Total>
</Branch>
<Branch>
<Id> 2 </Id>
<Name> 名称A-4 </Name>
<Total> 58156.22 </Total>
</Branch>
</SubRecord>
</Record>
<Record>
......
[解决办法]
http://www.ujx.cn/program/Delphi/delphi02/200604/21835.html
