求助，位图24位转16位不解之处
// process each line and copy it into the primary buffer
for (int index_y = 0; index_y < SCREEN_HEIGHT; index_y++)
{
for (int index_x = 0; index_x < SCREEN_WIDTH; index_x++)
{
// get BGR values, note the scaling down of the channels, so that they
// fit into the 5.6.5 format
UCHAR blue = (bitmap.buffer[index_y*SCREEN_WIDTH*3 + index_x*3 + 0]) >> 3,
green = (bitmap.buffer[index_y*SCREEN_WIDTH*3 + index_x*3 + 1]) >> 3,
red = (bitmap.buffer[index_y*SCREEN_WIDTH*3 + index_x*3 + 2]) >> 3;
// this builds a 16 bit color value in 5.6.5 format (green dominant mode)
USHORT pixel = _RGB16BIT565(red,green,blue);
// write the pixel
primary_buffer[index_x + (index_y*ddsd.lPitch >> 1)] = pixel;
} // end for index_x
} // end for index_y
加载进的24位位图存在bitmap里，位图大小与屏幕大小一致。每像素转16位后刷到屏幕缓存里。
请问
blue = (bitmap.buffer[index_y*SCREEN_WIDTH*3 + index_x*3 + 0]) >> 3;
为什么要右移三位？
相关定义如下：
typedef unsigned char UCHAR;
typedef unsigned short USHORT;
// this builds a 16 bit color value in 5.6.5 format (green dominate mode)
#define _RGB16BIT565(r,g,b) ((b & 31) + ((g & 63) << 5) + ((r & 31) << 11))
// container structure for bitmaps .BMP file
typedef struct BITMAP_FILE_TAG
{
BITMAPFILEHEADER bitmapfileheader; // this contains the bitmapfile header
BITMAPINFOHEADER bitmapinfoheader; // this is all the info including the palette
PALETTEENTRY palette[256]; // we will store the palette here
UCHAR *buffer; // this is a pointer to the data
} BITMAP_FILE, *BITMAP_FILE_PTR;
谢谢！
[解决办法]
'RGB16BIT565',也就是3个8位（24）要变成 5,6,5位。这样就可以在16位中表示（5+6+5)
[解决办法]
试试移两位，RGB16bit有两种模式565和555
