首页 诗词 字典 板报 句子 名言 友答 励志 学校 网站地图
当前位置: 首页 > 教程频道 > JAVA > Java Web开发 >

最后25分了,求一句简单的代码,在JSP中嵌一句SQL!解决办法

2012-01-19 
最后25分了,求一句简单的代码,在JSP中嵌一句SQL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!SELECT*FROMwang.linc

最后25分了,求一句简单的代码,在JSP中嵌一句SQL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
"SELECT   *   FROM   wang.linchangfenbu   WHERE   ???????? "   where后面的判定条件不会写了.   想将下面程序中comments作为判定条件.试试挺多方法都得到无效的运算符的结果.应该不难,只是我太笨了.呵呵,那么前辈帮写出来吧.谢谢啦.
<%@   page   contentType= "text/html;   charset=GB2312 "   language= "java "   import= "java.io.*,   java.sql.*,   javax.sql.* "%>  
<%@   page   import= "oracle.jdbc.*,   oracle.sql.*   "%>  

<html>  
<body>                      
<%  
          request.setCharacterEncoding( "GBK ");
          String   comments=request.getParameter( "comments ");
               

  //       Connect   to   the   database  
          Class.forName( "oracle.jdbc.driver.OracleDriver ").newInstance();
          String   url= "jdbc:oracle:thin:@localhost:1521:myoracle ";  
         
          String   user= "wang ";  
          String   password= "yan0625 ";  
          Connection   conn=   DriverManager.getConnection(url,user,password);    


          Statement   stmt   =   conn.createStatement   ();  
          ResultSet   rs   =    
              stmt.executeQuery( "SELECT   *   FROM   shen01.linchangfenbu   WHERE   ???????? "   );  
              out.println( " <table   border= '1 '   align= 'center '   > ");    
      out.println( " <tr   align= 'center '> ");
      out.println( " <th> ttt1 </th> <th> ttt2 </th> <th> ttt3 </th> ");  
    out.println( " </tr> ");
    while(rs.next())   {  
                                        out.println( " <tr   align= 'center '> ");
   
                      out.println   ( " <td> "+rs.getString( "ttt1 ")+ " </td> ");
    out.println( " <td> "+rs.getString( "ttt2 ")+ " </td> ");
    out.println( " <td> "+rs.getString( "ttt3 ")+ " </td> ");
    out.println( " </tr> ");
    }
    out.println( " </table> ");
         

 
      //   Close   input   and   output   streams  
      rs.close();  
     
      conn.close();


%>

</body>

</html>


[解决办法]
很简单
String sql = "SELECT * FROM shen01.linchangfenbu WHERE " + comments;
ResultSet rs =
stmt.executeQuery(sql );
用动态的方式生成SQL就可以了
[解决办法]
你把前面页面的textarea值取出来,再用连接字符串把整个的sql语句拼起就是查询条件了.
String comments=request.getParameter( "comments ");
String sql = "SELECT * FROM shen01.linchangfenbu WHERE " + comments;
Statement stmt = conn.createStatement ();
ResultSet rs =stmt.executeQuery(sql );

热点排行