如何根据list一个值对这个list重新排序

怎么根据list一个值对这个list重新排序
这是两个list得出来得结果集用得sql "select do.id, c.startTime ，c.ani from depat order by startTime desc";

我把两个list合并成一个list后由于顺序乱了，我还想根据里面一个startTime属性值来排序应该怎么做啊，排序完放入另外一个新的list

  
List resultSet = new ArrayList();
List resultSetOne = null;
List resultSetTwo = null;
   
resultSetOne = queryOne.list();
resultSetTwo = queryTwo.list();
resultSet.addAll(resultSetOne);
resultSet.addAll(resultSetTwo);

[解决办法]
比较器的定义,就是一个实现Comparator接口定义
实现如下:

Java code

package bt_lose;import java.util.ArrayList;import java.util.Collections;import java.util.Comparator;import java.util.List;/** * 简单实体 *  * @author botao *  */public class User {    @Override    public String toString() {        return "User: id=" + uid + "  uname=" + uname + "  upass=" + upass;    }    private int uid;    private String uname;    private String upass;    public String getUname() {        return uname;    }    public void setUname(String uname) {        this.uname = uname;    }    public String getUpass() {        return upass;    }    public void setUpass(String upass) {        this.upass = upass;    }    public User() {    }    public User(int id, String name, String pass) {        this.uid = id;        this.uname = name;        this.upass = pass;    }    public int getUid() {        return uid;    }    public void setUid(int uid) {        this.uid = uid;    }    public static void main(String[] args) {        List<User> list = new ArrayList<User>();        list.add(new User(1, "name1", "pass1"));        list.add(new User(3, "name3", "pass3"));        list.add(new User(2, "name2", "pass2"));        list.add(new User(4, "name4", "pass4"));        System.out.println("before sort");        for (User user : list) {            System.out.println(user);        }        //比较器是通过匿名类来做的        Collections.sort(list, new Comparator<User>() {            public int compare(User arg0, User arg1) {                //定义如何比较                return arg0.getUid() - arg1.getUid();            }        });        System.out.println("after sort");        for (User user : list) {            System.out.println(user);        }    }}
[解决办法]
package test1.sort;

import java.util.Comparator;

public class MyComparator implements Comparator {

public int compare(Object o1, Object o2) {

MyObject obj1 = (MyObject) o1;
MyObject obj2 = (MyObject) o2;

return obj1.getStartTime().before(obj2.getStartTime())?1:0;
}

}

package test1.sort;

import java.util.Date;

public class MyObject {

private int id;
private Date startTime;
private String ani;

public MyObject(int id,Date startTime,String ani) {
this.id = id;
this.startTime = startTime;
this.ani = ani;
}

public String getAni() {
return ani;
}
public void setAni(String ani) {
this.ani = ani;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public Date getStartTime() {
return startTime;
}
public void setStartTime(Date startTime) {
this.startTime = startTime;
}
}

package test1.sort;

import java.text.ParseException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Test {

/**
 * @param args
 * @throws ParseException   
 
 */
public static void main(String[] args) throws ParseException {
java.text.SimpleDateFormat format = new java.text.SimpleDateFormat("yyyyMMDD");

List list = new ArrayList();
MyObject o1 = new MyObject(1,format.parse("20071220"),"1");
MyObject o2 = new MyObject(2,format.parse("20071219"),"1");
MyObject o3 = new MyObject(3,format.parse("20071217"),"1");
MyObject o4 = new MyObject(4,format.parse("20071222"),"1");
MyObject o5 = new MyObject(5,format.parse("20071223"),"1");
list.add(o1);
list.add(o2);
list.add(o3);
list.add(o4);
list.add(o5);
Collections.sort(list, new MyComparator());
for (int i = 0; i < list.size(); i++) {
MyObject temp = (MyObject)list.get(i);
System.out.println(format.format(temp.getStartTime()));
}
}

}