求正则表达式~该如何处理

求正则表达式~
^abc^def^ghi^jkl^mnopqrst^  
给定了以上字符串，如何把两个 "^ "中的内容用正则表达式解析出来？  
结果应该为  
abc  
def  
ghi  
jkl  
mnopqrst  
谢谢~~！！

[解决办法]
这样 不需要 正则吧
string a = "^abc^def^ghi^jkl^mnopqrst^ ";
string[] myArr = a.Split( '^ ');
[解决办法]
正则表达式可以用这个 @ "\^([^\^]+)\^ ";
[解决办法]
正则表达式可以用(? <=\^).*?(?=\^)

就你这一问题，可以这样做

string yourStr = "^abc^def^ghi^jkl^mnopqrst^ ";
string resultStr = Regex.Replace(yourStr, @ "(? <=\^)(.*?)(?=\^) ", "$1\n ").Replace( "^ ", " ");

或者
string yourStr = "^abc^def^ghi^jkl^mnopqrst^ ";
MatchCollection mc = Regex.Matches(yourStr, @ "(? <=\^)(.*?)(?=\^) ", RegexOptions.IgnoreCase);
foreach (Match m in mc)
{
richTextBox1.Text += m.Groups[1].Value + "\n ";
}
[解决办法]
@ "\^([^\^]+)\^ " 会漏掉

楼上的正确
foreach (Match m in Regex.Matches(yourStr, @ "(? <=\^)(.*?)(?=\^) "))
richTextBox1.AppendText(m.Result( "$1 ") + "\r\n ");