求横向菜单代码，用javascript做！特急趴求！该如何解决

2012-01-09

求横向菜单代码，用javascript做！！！！特急，趴求！！！！！！我其实是想作如下操作。点击一级菜单，然后把菜单项的id

求横向菜单代码，用javascript做！！！！特急，趴求！！！！！！
我其实是想作如下操作。
点击一级菜单，然后把菜单项的id传到数据库，通过从数据库中提取二级菜单项，放入datalist控件中显示出来，然后单击相应的二级菜单项，连接到相应的网页。
如果大家有好的例子，帮忙推荐下。如果好使，可加分。谢谢。
效果如下：
|人事管理|项目管理|文档管理|
当点击“人事管理”后
下边出现：|人员录入|人员查询|（这是用DATALIST控件显示出来的）！！！
当点击，“人员录入”时，将显示相应窗口
十分着急，各位大侠帮忙，江湖告急！！！！！！

[解决办法]
从数据库中取出还要用javascript做???
[解决办法]
www.smallrain.net
[解决办法]
<script type=text/javascript>
/**
*菜单的构造,需要绑定到onload
*/
startList = function() {
if (document.all&&document.getElementById) {
dropmenuRoot = document.getElementById( "dropmenu ");
for (i=0; i <dropmenuRoot.childNodes.length; i++) {
node = dropmenuRoot.childNodes[i];
if (node.nodeName== "LI ") {
node.onmouseover=function() {
this.className+= " over ";
//开始灌水
for(j=0;j <this.childNodes.length;j++){
if (this.childNodes[j].nodeName== "UL "){
if (this.childNodes[j].childNodes[0].nodeName== "LI "){
if (this.offsetLeft+this.childNodes[j].childNodes.length*this.childNodes[j].childNodes[0].offsetWidth-dropmenuRoot.offsetLeft> dropmenuRoot.offsetWidth){
var len=this.childNodes[j].childNodes.length*this.childNodes[j].childNodes[0].offsetWidth; //菜单的长度
(len> dropmenuRoot.offsetWidth) ? this.childNodes[j].style.width=776+ "px " : this.childNodes[j].style.width=len+ "px "; //给ul设置宽度如果子菜单比较多，大于容器的宽度，那么ul的宽度就是容器的宽度
len =this.offsetLeft+len-dropmenuRoot.offsetLeft-dropmenuRoot.offsetWidth;
(len> this.offsetLeft-dropmenuRoot.offsetLeft) ? this.childNodes[j].style.marginLeft=-(this.offsetLeft-dropmenuRoot.offsetLeft) : this.childNodes[j].style.marginLeft=-len+ "px ";
}
}
}
}
}
//灌水完毕
node.onmouseout=function() {
this.className=this.className.replace( " over ", " ");
}
}
}
}
}
window.onload=startList;
</script>
<body>
<div id= "nav ">
<ul id= "dropmenu ">
<li> <a href= "# "> Home </a> </li>
<li> <a href= "# "> About </a>
<ul>
<li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>
<li> <a href= "# "> Drop Down Menu </a> </li>
<li> <a href= "# "> Offices </a> </li>
</ul>
</li>
<li> <a href= "# "> Services </a>
<ul>
<li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>
<li> <a href= "# "> Drop Down Menu </a> </li>
<li> <a href= "# "> Offices </a> </li>
</ul>
</li>
<li> <a href= "# "> Home </a> </li>
<li> <a href= "# "> About </a>
<ul>
<li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>

<li> <a href= "# "> Drop Down Menu </a> </li>
<li> <a href= "# "> Offices </a> </li> <li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>

</ul>
</li>
<li> <a href= "# "> Services </a>
<ul>
<li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>
<li> <a href= "# "> Drop Down Menu </a> </li>
<li> <a href= "# "> Offices </a> </li>
<li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>
<li> <a href= "# "> Drop Down Menu </a> </li>
<li> <a href= "# "> Offices </a> </li>
<li> <a href= "# "> History </a> </li>
<li> <a href= "# "> Team </a> </li>
<li> <a href= "# "> Drop Down Menu </a> </li>

</ul>
</li>
<li> <a href= "# "> Home </a> </li>
</ul>
</div>
</body>
</html>
[解决办法]
<html>
<head>
<meta http-equiv= "Content-Type " content= "text/html; charset=gb2312 ">
<title> ... </title>
<STYLE type=text/css> .sec1 {
BORDER-RIGHT: gray 1px solid; BORDER-TOP: #ffffff 1px solid; BORDER-LEFT: #ffffff 1px solid; CURSOR: hand; COLOR: #000000; BORDER-BOTTOM: #ffffff 1px solid; BACKGROUND-COLOR: #FF99CC
}
.sec2 {
BORDER-RIGHT: gray 1px solid; BORDER-TOP: #ffffff 1px solid; FONT-WEIGHT: bold; BORDER-LEFT: #ffffff 1px solid; CURSOR: hand; COLOR: #000000; BACKGROUND-COLOR: #FFE1F5
}
.main_tab {
BORDER-RIGHT: gray 1px solid; BORDER-LEFT: #ffffff 1px solid; COLOR: #000000; BORDER-BOTTOM: gray 1px solid; BACKGROUND-COLOR: #FFE1F5
}
</STYLE>
<SCRIPT language=javascript>
function secBoard(n)
{
for(i=0;i <secTable.cells.length;i++)
secTable.cells[i].className= "sec1 ";
secTable.cells[n].className= "sec2 ";
for(i=0;i <mainTable.tBodies.length;i++)
mainTable.tBodies[i].style.display= "none ";
mainTable.tBodies[n].style.display= "block ";
}
</SCRIPT>
</head>

<body>
<TABLE id=secTable cellSpacing=0 cellPadding=0 width=300 border=0 class= "css3 ">
<TBODY>
<TR align=middle height=20>

<TD class=sec2 onclick=secBoard(0) width= "10% "> 人事管理 </TD>

<TD class=sec1 onclick=secBoard(1) width= "10% "> 项目管理 </TD>

<TD class=sec1 onclick=secBoard(2) width= "10% "> 文档管理 </TD>

</TR> </TBODY> </TABLE>

<TABLE class=main_tab id=mainTable height=180 cellSpacing=0 cellPadding=0 width=300 border=0>
<TBODY style= "DISPLAY: block ">
<TR>
<TD vAlign=top align=middle> <BR> <BR>

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求横向菜单代码，用javascript做！特急趴求！该如何解决