求一能够从一数组中提出相同元素的函数，请指点一二，小弟刚开始学，还请各位老师赐教

求一能够从一数组中提出相同元素的函数，在线等！请各位高手指点一二，小弟刚开始学，还请各位老师赐教！
要求！：
  比如此函数名字为：bindGrid(string [],int i)
  参数string []即表示数组，i呢表示string []数组的元素相同的个数！
  例如：bindGrid(string [],5)；即提取这个string []数组中出现5次的元素；
  请各位给个例子！
  拜托！

[解决办法]
可以在数据查询的时候直接做。
或你自己写一个类似count(*) ... group by ... having count(*)=5 的方法。

C# code

    static string GetRepeatedElement(string[] strs, int repeats)    {        Dictionary<string, int> dict = new Dictionary<string, int>();        foreach (string s in strs)        {            if (dict.ContainsKey(s)) dict[s]++;            else dict[s] = 1;        }        foreach (string s in dict.Keys)        {            if (dict[s] == repeats) return s;        }        return null;    }
[解决办法]
C# code
private string[] bindGrid(string[] array,int i){    HashTable ht = new HashTable();    foreach(string s in array)    {        if(ht.ContainsKey(s))            ht[s]=Convert.ToInt32(ht[s])+1;        else            ht.Add(s,1);    }    List<string> list=new List<string>();    IDictionaryEnumerator ide = ht.GetEnumerator();    while(ide.MoveNext())    {        if(ide.Value.ToString()==i)            list.Add(ide.Value.ToString());    }    string[] result= list.ToArray();    return result;}
[解决办法]
string[] asa = new string[] {"1","1","2","1","3","3","1","5","3","3","3","3","3" };  
           bindGrid(asa,5);  

private static void bindGrid(string[] n,int max)  
       {  
           int count=0;  
           for (int i = 0; i < n.Length;i++ )  
           {               
               for (int j = i + 1; j < n.Length;j++ )  
               {  
                   if (count-1 > max)  
                   {  
                       Console.Write(n[i].ToString());  
                       Console.Read();  
                   }  
                   else  
                   {  
                       if (n[i].Equals(n[j])) count++;  
                   }  
               }  
           }  
       }
[解决办法]
C# code
        string[] str = new string[] { "a", "b", "a", "c", "d", "e", "c", "a" ,"e","a","c","c","c","a"};        public System .Collections .ArrayList  bindGrid(string[] str, int i)        {            int counter=0;                     System.Collections.ArrayList alist = new System.Collections.ArrayList();            for (int j = 0; j < str.Length; j++)            {                counter = 0;                for (int k = 0; k < str.Length; k++)                {                    if (str[j] == str[k])                        counter++;                }                if (counter == i&& alist .IndexOf (str [j])<0)//滤除相同元素                    alist.Add(str[j]);                            }            return alist;                   }
[解决办法]
返回string[] 的话可参考5楼的方式.
return (string [])alist.ToArray(typeof(string));

[解决办法] 
 
来个正则版的
C# code
static List<string> getRepeatElement(string[] array,int n)        {            StringBuilder sb = new StringBuilder(50);            List<string> list = new List<string>();            Array.Sort(array);            foreach (string s in array)                sb.Append(s+",");            foreach (System.Text.RegularExpressions.Match match in System.Text.RegularExpressions.Regex.Matches(sb.ToString(), @"(?<repeat>\w\,)(?:\k<repeat>){" + (n-1) + "}"))            {                 string element = match.ToString().Substring(0,match.ToString().IndexOf(",")+1);                if (!System.Text.RegularExpressions.Regex.IsMatch(sb.ToString(), @"("+element + "){" + (n+1) + "}"))                    list.Add(element);            }            return list;        }